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Fofino [41]
2 years ago
9

(x5 + y5) ÷ (x + y) please answer ASAP

Mathematics
1 answer:
Shkiper50 [21]2 years ago
3 0

Answer:

\frac{x^5+y^5}{x+y}=x^4-x^3y+x^2y^2-xy^3+y^4

Step-by-step explanation:

Given the expression

\left(x^5+y^5\right)\div \left(x+y\right)

\mathrm{Apply\:factoring\:rule:\:}x^n+y^n=\left(x+y\right)\left(x^{n-1}-x^{n-2}y+\:\dots \:-\:xy^{n-2}\:+\:y^{n-1}\right)\:\quad \quad \mathrm{n\:is\:odd}

x^5+y^5=\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)

=\frac{\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)}{x+y}

Cancel the common factor: x+y

=x^4-x^3y+x^2y^2-xy^3+y^4

Thus,

\frac{x^5+y^5}{x+y}=x^4-x^3y+x^2y^2-xy^3+y^4

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