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3 years ago

Solve x/4 = 8please help me find what x is

Mathematics

2 answers:

Alex73 [517]3 years ago

8 0

Answer:

x = 32

Step-by-step explanation:

x/4 = 8

<=> x = 8 . 4

<=> x = 32

denis-greek [22]3 years ago

3 0

Multiply by 4 on both sides to get x=32.

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3 years ago

Solve the inequality,

son4ous [18]

The answer is -9-18x
27−9x−9(x+4)=

27−9x−(9x+36)=

27−9x−9x−36=

Collect like terms.

(27−36)+(−9x−9x)= −9−18x

5 0

3 years ago

The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar

Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

$\bar x$ represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=10-1=9$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical values.

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

$\chi^2_{\alpha/2}=19.022$

$\chi^2_{1- \alpha/2}=2.700$

And replacing into the formula for the interval we got:

$\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}$

$10.892 \leq \sigma^2 \leq 76.736$

Now we just take square root on both sides of the interval and we got:

$3.30 \leq \sigma \leq 8.76$

So the best option would be:

3.30<σ<8.76

7 0

3 years ago

Which statement is true regarding the sides of a triangle

yulyashka [42]

The statement that is true regarding the sides of a triangle is the last one because the top and bottom have to be identical to each other and the sides have to be identical to each other.

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2 years ago

The College Student Journal (December 1992) investigated differences in traditional and nontraditional students, where nontradit

shutvik [7]

Answer:

There is a 0.13% probability that the random sample of 100 nontraditional students have a mean GPA greater than 3.65.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

For this problem, we have that:

Based on the study results, we can assume the population mean and standard deviation for the GPA of nontraditional students is $\mu = 3.5$ and $\sigma = 0.5$ .