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VikaD [51]
3 years ago
7

Please help me. Thank you. I appreciate it :)

Mathematics
2 answers:
puteri [66]3 years ago
7 0

Step-by-step explanation:

the answer should be 18

Aleonysh [2.5K]3 years ago
7 0

Answer:

Area = Big one - small one = 4 x (3 + 2 + 1) - 3 x 2 = 24 - 6 = 18 cm2.

=> Option B is correct.

Hope this helps!

:)

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Two step equation , please help thank you
sertanlavr [38]
The equation is 114 = 1/3p - 3
To solve it:
117 = 1/3p
351=p
There are 351 pages in the novel.
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3 years ago
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Plsss helppp<br> WILL GIVE BRAINLIEST
Ann [662]

Answer:

I thinks it's point 2 and if it's wrong I am sorry for that

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A radioactive substance decays at a continuous rate of 17% per year, and 250 mg of the substance is present in the year 2009.
yaroslaw [1]

Answer:

a) A(t) = 250 (1-0.17)^t = 250(0.83)^t

b) A(t=14) = 250 (0.83)^{14}= 18.408 mg

c) For this case we want to find when the quantity is below 25 mg, so we can do this:

25 = 250 (0.83)^t

We can divide both sided by 250 and we got:

0.1 = 0.83^t

Now we can apply natural log on both sides and we got:

ln(0.1) = t ln (0.83)

And if we solve for t we got:

t = \frac{ln(0.1)}{ln(0.83)}= 12.358 years

So the answer for this case would be 12.358 years after.

Step-by-step explanation:

Part a

For this case we know that the decay rate per year is about 17% or 0.17 in fraction and the initial amount is 250 mg for 2009, we can define the model like this:

A(t) = A_o (1-r)^t

Where A represent the amount of the substance in mg, r the decay rate = 0.17 and t the number of years after 2009.

Our model for this case would be:

A(t) = 250 (1-0.17)^t = 250(0.83)^t

Part b

For this case we have that t= 2023-2009=14 years, so then we can find the amount of substance like this:

A(t=14) = 250 (0.83)^{14}= 18.408 mg

Part c

For this case we want to find when the quantity is below 25 mg, so we can do this:

25 = 250 (0.83)^t

We can divide both sided by 250 and we got:

0.1 = 0.83^t

Now we can apply natural log on both sides and we got:

ln(0.1) = t ln (0.83)

And if we solve for t we got:

t = \frac{ln(0.1)}{ln(0.83)}= 12.358 years

So the answer for this case would be 12.358 years after.

6 0
3 years ago
Practice analyzing quantitative relationships.
ANEK [815]

Answer:

Sorry can't see on school computer :(

Step-by-step explanation:

5 0
3 years ago
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Brainliest to whoever gets this correct The graph of g(x), shown below, resembles the graph of f(x) = x4 - x2, but it has been c
shusha [124]
<h3>Answer: C.  g(x) = x^4 - x^2 + 0.5</h3>

Why is this?

We start with x^4 - x^2, which is the original f(x) function. Adding some number to this result will increase the y coordinate of any point on the f(x) function. This is because y = f(x). The only thing that matches is choice C, where we shift the graph up 0.5 units. We say that g(x) = f(x) + 0.5

Choice D goes in the opposite direction, and shifts the graph down 0.5 units.

Choices A and B shift the graph horizontally to the right 0.5 units and to the left 0.5 units respectively.

3 0
3 years ago
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