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xxMikexx [17]
3 years ago
6

Write the sum of 120 36 as the product of their gf and another sum

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
5 0
120 + 36 = 12(10 + 3)
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Solve 3(4x-1)=12x +7
telo118 [61]

Answer:

there are no solutions

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the center and radius of the circle described by the equation
Debora [2.8K]
Complete the square fr x and y's sepreatly to get into form
(x-h)²+(y-k)²=r²
the center is (h,k) and radius is r

so


group x's and y's seperatly
(4x²-10x)+(4y²+24y)+133/4=0
undistribute leading confident from each
4(x²-2.5x)+4(y²+6y)+133/4=0
take 1/2 of each linear confident and square it and add negative and positive inside the parenthasees
-2.5/2=-1.25 (-1.25)²=1.5625
6/2=3, 3²=9
4(x²-2.5x+1.5625-1.5625)+4(y²+6y+9-9)+133/4=0
factor perfect squares
4((x-1.25)²-1.5625)+4((y+3)²-9)+133/4=0
expand
4(x-1.25)²-6.25+4(y+3)²-36+133/4=0
4(x-1.25)²+4(y+3)²-9=0
add 9 to both sides
4(x-1.25)²+4(y+3)²=9
divide both sides by 4
(x-1.25)²+(y+3)²=9/4
(x-1.25)²+(y+3)²=(3/2)²

the center is (1.25,-3) and the radius is 1.5
8 0
3 years ago
Evaluate (y - 9) + (3 + x), when y = 15 and x = 5​
svet-max [94.6K]

Answer:

14

Step-by-step explanation:

It says 'Evaluate (y - 9) + (3 + x), when y = 15 and x = 5​'.

So we'd put 15 in y's place. It'll look like this (15 - 9).

Then we'd put 5 in x's place. It'll look like this (3 + 5).

You subtract (15 - 9) which equals 6. And you'd add (3 +5) which equals 8. You add 6 + 8 together since those are your answer for the parentheses. Your final should be 14. Hopefully this helped!

5 0
2 years ago
Someone help me with this
Jet001 [13]

2a. 14,9; 2b. 15,4; 2c. 30,8; 3. 32

For 2a., you have to set it up like this: csc 48° = 20⁄x [OR sin 48° = ˣ⁄20]. Then you would have to isolate the variable by getting rid of the denominator. The cosecant function has an extra step because you will get xcsc 48° = 20. As stated, isolate the variable; this time, divide by csc 48°. This is what 20 will be divided by to get your x, whereas the other side cancels out. Then you have to round to the nearest tenth degree.

For 2b., you have to set it up like this: sec 39° = ˣ⁄12 [OR cos 39° = 12⁄x. Then you would have to isolate the variable by getting rid of the denominator. The cosine function has an extra step because you will get xcos 39° = 12. As stated, isolate the variable; this time, divide by cos 39°. This is what 12 will be divided by to get your x, whereas the other side cancels out. Then you have to round to the nearest tenth degree.

For 2c., you have to set it up like this: cot 64° = 15⁄x [OR tan 64° = ˣ⁄15]. Then you would have to isolate the variable by getting rid of the denominator. The cotangent function has an extra step because you will get xcot 64° = 15. As stated, isolate the variable; this time, divide by cot 64°. This is what 15 will be divided by to get your x, whereas the other side cancels out. Then you have to round to the nearest tenth degree.

Now, for 3., it is unique, but similar concept. In this exercise, we are solving for an angle measure, so we have to use inverse trigonometric ratios. So, we set it up like this: cot⁻¹ 1⅗ = m<x [OR tan⁻¹ ⅝ = m<x]. We simply input this into our calculator and we get 32,00538321°. When rounded to the nearest degree, we get 32°.

WARNING: If you use a graphing calculator, you have to input it uniquely because most graphing calculators do not have the inverse trigonometric ratios programmed in their systems. This is how you would write this: tan⁻¹ 1⅗⁻¹. You set 1⅗ to the negative first power, ALONG WITH the inverse tangent function, because without it, your answer will be thrown off. Since Cotangent and Tangent are multiplicative inverses of each other, that is the reason why the negative first power is applied ALONG WITH the inverse tangent function.

**NOTE: 1⅗ = 8⁄5

Take into consideration:

sin <em>θ</em> = O\H

cos <em>θ</em><em> </em>=<em> </em>A\H

tan <em>θ</em><em> </em>= O\A

sec <em>θ</em><em> </em>= H\A

csc <em>θ</em><em> </em>= H\O

cot <em>θ</em><em> </em>= A\O

I hope this helps you out alot, but if you are still in need of assistance, do not hesitate to let me know and subscribe to my channel [username: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

7 0
3 years ago
F(n)=−11+22(n−1), left parenthesis, n, right parenthesis, equals, minus, 11, plus, 22, left parenthesis, n, minus, 1, right pare
prisoha [69]

Answer:

a_1 = -11\\\\a_n = a_{(n - 1)} + 22

Step-by-step explanation:

An arithmetic sequence is generally given as:

f(n) = a + (n - 1)d

where a = first term and f(n) = nth term, d = common difference

The explicit formula given is:

f(n) = 11 + 22(n - 1)

The recursive formula is made of two statements, the first term and the formula showing how successive terms are related.

Mathematically, it is given as:

a_1 = a\\\\a_n = a_{(n - 1)} + d

Therefore, the recursive formula is:

a_1 = -11\\\\a_n = a_{(n - 1)} + 22

8 0
3 years ago
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