Answer:
c^3 + c^2 - 7c + 20
Step-by-step explanation:
First, expand the expression using distributive property.
c^2(c+4) - 3c(c+4) + 5(c+4)
c^3 + 4c^2 - 3c^2 - 12c + 5c + 20
Lastly, simplify like terms.
c^3 + c^2 - 7c + 20
Answer:
The distance reduces to 0 as you go from 0° to 90°
Step-by-step explanation:
The question requires you to find the distance using different values of L and check the trend of the values.
Given C=2×pi×r×cos L where L is the latitude in ° and r is the radius in miles then;
Taking r=3960 and L=0° ,
C=2×
×3960×cos 0°
C=2×
×3960×1
C=7380
Taking L=45° and r=3960 then;
C= 2×
×3960×cos 45°
C=5600.28
Taking L=60° and r=3960 then;
C=2×
×3960×cos 60°
C=3960
Taking L=90° and r=3960 then;
C=2×
×3960×cos 90°
C=2×
×3960×0
C=0
Conclusion
The values of the distance from around the Earth along a given latitude decreases with increase in the value of L when r is constant
The answer to the question is B
Hope this helps :)
Answer:
angle BOD = angle AOC
( cuz they are vertical opposite angles )
so angle BOD = 65°
Answer:
8.06
Step-by-step explanation:
I used my brain and paper. I don't want to have to explain it anymore sorry but yes I think that is the right answer.