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Anna [14]
3 years ago
5

2. Kelsey has a list of possible functions. Pick one of the g(x) functions below and then describe to Kelsey the key features of

g(x), including the end behavior, y-intercept, and zeros.
o g(x) = (x + 2)(x − 1)(x − 2)
o g(x) = (x + 3)(x + 2)(x − 3)
o g(x) = (x + 2)(x − 2)(x − 3)
o g(x) = (x + 5)(x + 2)(x − 5)
o g(x) = (x + 7)(x + 1)(x − 1)

Mathematics
1 answer:
Gemiola [76]3 years ago
3 0

Answer:

g(x) = (x + 2)(x − 1)(x − 2)

I picked the first one, because why not. :)

<u>End behavior.</u> This is a positive function; there are no negatives next to any of the xs. There are 3 xs, so it's a cubic; a positive cubic has a down-up end behavior.

<u>Y-intercept.</u> We can either graph this on the calculator/online or work it out algebraically. Multiply together the constants: +2 * -1 = -2, -2 * -2 = 4. So the y-intercept is at y = 4. (0,4). I've also attached the graph.

<u>Zeros / x-intercept.</u> This is really simple: set g(x) equal to 0, separate these three parenthesis (x+2) (x-1) and (x-2) into three equations by the Zero Product Property.

x+2 = 0

x = -2

x-1 = 0

x = 1

x-2 = 0

x = 2

So the function has three zeros at (-2,0) (1,0) and (2,0).

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2k^2 + 9k = -7 using quadratic equation
Pepsi [2]

Answer:(k+1)(2K+7)

Step-by-step explanation:

Using the quadratic formula

X=-b±-√b^2-4ac/2a

ax^2+bx+c=0

2k^2+9k+7=0

In this case a=2,b=9,c=7

-9+-√9^2-4(2)(7)/2(2)

(-9+√25)/4=-9+5/4=-1

(-9-√25)/4=-14/4 =-7/2

X=-1,X=-7/2

So (K+1)(k+7/2)

So (k+1)(2k+7)

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3 years ago
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What is the equation in point−slope form of the line passing through (1, 2 and (2, 5?
Nimfa-mama [501]
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A store has shirts on display. Seven of the shirts are red. There are 5 more blue shirts than green shirts. There are 2 fewer ye
mixas84 [53]

Answer:

7 red shirts

6 green shirts

11 blue shirts

4 yellow shirts

Step-by-step explanation:

Let y represent the number of green shirts.

So y+5 is the number of blue shirts.

And y-2 is the number of yellow shirts.

And we have 5 red shirts.

Therefore,

7+5+y+y-2+y=28

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