Answer:
Sum of the first five terms of the geometric sequence in which a1=5 and r=1/5 is
Step-by-step explanation:
We need to find sum of the first five terms of the geometric sequence in which a1=5 and r=1/5
The formula used to find sum of the geometric sequence is:
Where a is the first term, r is the common ratio and n is the number of terms
Now finding sum of the first five terms of the geometric sequence
We have a=5, r=1/5 and n=5
Putting values in the formula:
So, sum of the first five terms of the geometric sequence in which a1=5 and r=1/5 is
Answer:
The radius is r=5 units
Step-by-step explanation:
we know that
The equation of the circle in standard form is equal to
where
(h,k) is the center and r is the radius
we have
Convert to standard form
Group terms that contain the same variable, and move the constant to the opposite side of the equation
Complete the square twice. Remember to balance the equation by adding the same constants to each side
Rewrite as perfect squares
therefore
The center is the point (6,-3) and the radius is r=5 units
Assignments
Let
Jill = J
Beth = B
Meg = M
Sounds like Beth is the youngest.
J = M - 2
B = 1/2 M
Explanation
B = 1/2 M. This means that Beth is 1/2 as old as Meg.
J = M - 2 This means that Jill is 2 years younger than Meg.
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Comment
I don't think you can go to three statements. You need one more statement than you've given us.
(2a + 3b)^2 = 4a^2 + 12ab + 9b^2 =
((4a^2 - 6ab + 9b^2) + 18ab) = 144
4a^2 - 6ab + 9b^2 = 144 - 18 ab
8a^3 + 27b^3 = (2a + 3b)(4a^2 - 6ab + 9b^2)
8a^3 + 27b^3 = (2a + 3b)*(144 - 18ab)
8a^3 + 27b^3 = 12 * (144 - 18ab)
= 12 * ( 144 - 18*6) since ab = 6
= 12 * (144 - 108)
= 12 * (36)
= 432 <<<<==== answer