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mojhsa [17]
3 years ago
6

Solve the quadratic equation by square roots: 1. 4x²= 81 2. (4x-3)²+7=39

Mathematics
1 answer:
Nataly [62]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

(1)

given

4x² = 81 ( divide both sides by 4 )

x² = \frac{81}{4} ( take the square root of both sides )

x = ± \sqrt{\frac{81}{4} } = ± \frac{9}{2}

---------------------------------------------------------------------

(2)

subtract 7 from both sides

(4x - 3)² = 32 ( take the square root of both sides )

4x - 3 = ± \sqrt{32} = ± 4\sqrt{2}

Add 3 to both sides

4x = 3 ± 4\sqrt{2} ( divide both sides by 4 )

x = \frac{3}{4} ± \sqrt{2}

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Which of the following best describes the expression 4(y + 6)?
Kryger [21]

Answer:

4y + 24

Step-by-step explanation:

4(y + 6) = 4y + 24

4 0
3 years ago
If the mean of a normal distribution is 210, what is the median of the
AleksandrR [38]

Answer:

210

Step-by-step explanation:

In a normal distribtuion mean=mode=median

so 210=median

3 0
3 years ago
How would you write 87 as a Roman numeral?
ddd [48]

Answer:

LXXXVII

Step-by-step explanation:

L=50 X=10 V=5 I=1

So basically you need to figure out what adds up to the 87. so use L, or 50. now XXX=30. so now you have 80 so we still have 7 left over, so we can write 7 I's or a 5, (V) and two I's. We should use the V and the I. So we take one V, or 5. and two I's which together is 7. which leads us too LXXXVII. also always remember to have the biggest number first, in this case the L (50).

7 0
3 years ago
Answer 18 and 19 in full sentences please
Murrr4er [49]
Can I see the rest of the problem of number 18 please
8 0
3 years ago
Evaluate the function.
Natali5045456 [20]
As you may already be familiar, these functions f(x) and g(x) are piecewise. They consist of multiple functions with different domains.

1. For #1, the given input is f(0). Since 0≤1, you should use the first equation to solve. f(0)=3(0)-1 ➞ f(0)=-1
2. Continue to evaluate the given input for the domains given. 1≤1, therefore f(1)=3(1)-1➞f(1)=2
3. 5>1, therefore f(5)=1-2(5)➞f(5)=-9
4. -4≤1; f(-4)=3(-4)-1➞f(-4)=-13
5. -3<0<1; g(0)=2
6. -3≤-3; g(-3)=3(-3)-1➞g(-3)=-10
7. 1≥1; g(1)=-3(1)➞g(1)=-3
8. 3≥1; g(3)=-3(3)➞g(3)=-9
9. -5≤-3; g(-5)=3(-5)-1➞g(-5)=-16

Hope this helps! Good luck!
5 0
3 years ago
Read 2 more answers
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