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strojnjashka [21]
2 years ago
13

I wanna pass this help me please-

Mathematics
1 answer:
Simora [160]2 years ago
5 0

Answer:

C

Step-by-step explanation: hope this helps :)

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How many units<br> above the x-axis<br> is the point<br> located at (9, 6)?<br> pls help
svetlana [45]

Answer:

6 units above the x-axis

Step-by-step explanation:

The pair (9,6) are a set of coordinates that indicate how far away from the origin (0,0) the point is.

The coordinates are written (x,y) where 'x' is how far to the left or right of the y-axis (vertical) the point is. The 'y' is how far above or below the x-axis (horizontal) the point is.

So in this case, the set of (9,6) means that the point is located at 9 units to the right of the origin and the y-axis and 6 units above the x-axis

4 0
3 years ago
Read 2 more answers
D/dx(sin x/2+cos x) = (a + b cos x)/(2+cos x)^2 find a and b.​
Talja [164]

Answer:

a = 1 and b = 2

Step-by-step explanation:

Using the Quotient Rule>

d/dx[(sin x)/(2+cos x) ]

=   [(2 + cos x) * cosx -  sin x * - sin x)]  /  (2 + cos x)^2

= 2cos x + cos^2x + sin ^2 x) /  (2 + cos x)^2

But cos^2x + sin^2x = 1 so we have:

(1 +  2 cos x)  /   (2 + cos x)^2

- so a = 1 and b = 2.

7 0
3 years ago
Which number sentence is true?
PIT_PIT [208]

I'm pretty sure it's 8.5 > 2.97

7 0
3 years ago
The area of a circle is 161 in. What is the radius?​
kirill [66]

Answer:

Approximately 7.16 in

Step-by-step explanation:

Hi there!

Area of a circle equation: A=\pi r^2 where r is the radius

Plug in the given area 161 in.²

161=\pi r^2

Divide both sides by π to isolate r²

\frac{161}{\pi} =\frac{\pi r^2}{\pi} \\\frac{161}{\pi} =r^2

Take the square root of both sides to isolate r

=r^2\\\sqrt{\frac{161}{\pi}} =r\\7.16=r

Therefore, the radius of the circle is approximately 7.16 in.

I hope this helps!

7 0
3 years ago
Can someone please help me and fast I'm stuck
vovikov84 [41]

Answer:

3 5/8

Step-by-step explanation:

6 4/8 - 2 7/8 = 4 -3/8 = 3 5/8

8 0
2 years ago
Read 2 more answers
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