<span>To solve for t, you will use the equation given: -16t^2 + 16t + 480 = 0. First, simplify the equation by dividing everything by 16: -t^2 + t + 30 = 0. Then complete reverse FOIL: (-t + 6)(t + 5) = 0. Next, set each of these equations to 0 separately, and solve for t. You will get t = 6, and t = -5. Since time can't be negative (Rose can't have hit the water after a negative number of seconds), the answer is 6. </span>
1 is really b, I just learned this
2 is really a
Answer:
y-intercept is (0, 2).
Step-by-step explanation:
The y-intercept occurs when x = 0 so:
2(0) + 3y = 6
y = 6/3 = 2.
So the y-intercept is (0, 2).
The profit is the amount left from you net income after your fixed expenses have been paid.
The amount earned by an individual or corporation after costs, allowances, and taxes is referred to as net income. Net income in company is what remains after all costs, such as salaries and wages, the cost of goods or raw materials, and taxes, have been paid.
Profit is a financial gain, specifically the sum obtained over that which was used to acquire, maintain, or produce the good or service.
Profit is the term used to describe the financial gain experienced when the revenue from a commercial activity exceeds the costs, costs, and taxes associated with maintaining that activity.
Hence the profit is the amount left from you net income after your fixed expenses have been paid.
Learn more about profit here:
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Answer:
V=258 πvu
Step-by-step explanation:
Knowing that to find the solid of revolution is V=πR²h, where R² = y = f(x) and h = a differential of x, we have that (according to the graph)
dV=π(4-32x)²dx, integrating on both sides ∫dV=π∫(4-32x)²dx;
let's solve ∫(4-32x)²dx = ∫(16-256x+1024x²)dx = 16∫dx-256∫xdx+1024∫x²dx =
16x-128x²+(1024/3)x³ evaluated between 0≤x≤1/8 plus 1/8∠x≤1, also
V=π/8(16.-128.+(1024/3))+π(16.1-128.1+(1024/3).1 = π/8(48-384+1024)/3+π(16.1-128.1+(1024/3).1 = π688/24+ π688/3 =
258 πvu
Note:
vu = volume units
Due to "inconvenience" to visualize graph 1 in its real scale its scale was modified in graph 2 and 3 respectively
