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jenyasd209 [6]
3 years ago
9

PLEASE HELP ME Find the area of the triangle.

Mathematics
1 answer:
Anika [276]3 years ago
6 0

Answer:

10

Step-by-step explanation:

area of triangle= 1/2(b×h)

hence 1/2×5×4=5×2= 10

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What is the missing number in the solution to 948 = 10 below?<br> A. 48<br> B. 4<br> C. 40<br> D. 80
denis23 [38]

Answer:

Step-by-step explanation:

8 0
3 years ago
A rectangle has a perimeter of 34 cm in an area of 52 cm squared it's length is 5 more than twice its width write and solve the
valina [46]

Let l be the length and w be the width of the rectangle.

Given perimeter of the rectangle

2(l+w)=34 \; l+w=17

Area of the rectangle is

lw=52

Also length is 5 more than twice its width,

l=2w+5

From the above equations

(l-w)^2=(l+w)^2-4lw=17^2-4*52=81\\ l-w=9,\; since \; l>w

Now 2l=9+17=26\;,l=13,w=4

The dimensions of the rectangle are length l=13, and width w=4.


8 0
4 years ago
Read 2 more answers
Name a point that is 20 units away from (5,-2)​
Fudgin [204]

Answer:

Distance between both points is 20units.

Applying the Distance between Points Formula

d= √(y₂-y₁)²+(x₂-x₁)²

x₁= 5 y₁=–2

x₂= ? y₂= ?

20 = √ [y -(-2)]² + (x - 5)²

Taking the square of both sides to eliminate the square root on the right.

20² = ( y + 2)² + (x - 5)²

400 = y² + 4y + 4 + x² – 10x + 25.

400 = x² + y² – 10x + 4y + 29.

x² + y² – 10x + 4y = 400 – 29

x² + y² – 10x + 4y = 371--------------eqn 1.

We called that eqn 1 cause we need another equation to solve this.

To solve an Equation with 2 variables... You need 2 equation.

To solve that of 3 variables.... you need 3 equations(Basic Math Rules).

We're dealing with 2 variables in this case(x, y).

Now

We'd need to think in order to create another equation that'll satisfy the distance or point.

We know that the distance between both Points(known and unknown) is 20.

Half that distance is 10.

The distance of 10 will occur at the center of these 2 points.

So lets apply the formula for Mid point to get the coordinate of the center.

Midpoint

let p be the x position and q be the y position of the midpoint

p = (x₁ + x₂)/2. q = (y₁ + y₂)/2

Starting from the know point (5 , -2)

x₁=5 y₁=–2

p = (5 + x)/2. q = (–2 + y)/2

p = (x + 5)/2 q = (y–2)/2.

This is the coordinate of the Midpoint.

Now We know that the distance between (5, -2) and [(x + 5)/2 , (y–2)/2] is 10(midpoint).

Applying the distance between points again.

d = √(y₂ - y₁)² + (x₂ - x₁)²

x₁= 5 y₁= -2

x₂= (x + 5)/2 y₂= (y–2)/2

10 = √[(y–2)/2 -(-2)]² + [ (x+5)/2 – 5)]²

10 = √[(y–2)/2 + 2]² + [(x+5)/2 – 5)]²

Squaring both sides to remove square root on the right and also Taking the LCM in each bracket

We have

10² = [ (y + 2)/2]² + [ (x–5)/2]²

Distributing the "2" on the denominator to each individual number in the parentheses.

100 = (y/2 + 1)² + (x/2 – 5/2)²

100 = y²/4 + y + 1 + x²/4 –5x/2 + 25/4.

Multiply through by 4 to clear fractions.

400 = y² + 4y + 4 + x² – 10x + 25

Rearranging

x² + y² – 10x + 4y = 371.

Hmm...

Equation 1 and 2 Are the Same.

Something is Wrong!

Pls Recheck the Question

I do believe that One value of the unknown point should be given.

I maybe be wrong somewhere else too.

Pls correct in the comment section if you spot it.

7 0
3 years ago
Whats the value of 8:3 ?
umka2103 [35]

Answer:

As a mixed number, 8/3 is equal to 2-2/3.

Step-by-step explanation:

6 0
3 years ago
The first step in solving 5 = 2 + is to subtract 2 from both sides of the equation.
Aleks [24]
Yes you should subtract 2 from the sides
7 0
4 years ago
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