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ankoles [38]
3 years ago
13

Helpppp plzzzz what is the measure of /_x

Mathematics
1 answer:
zaharov [31]3 years ago
4 0

Answer:

100

Step-by-step explanation:

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PLS ANSWER THIS ASAP WILL MARK BRAINLIEST!!!!
Morgarella [4.7K]

Answer:

x=27

Step-by-step explanation:

The formula for the volume of a pyramid is L*W*H/3

We know all three, being x, x, and x/9

So after we plug those in, we see that x^3/27 = 27

then solving for x we get √27*27 which is 27

Please Vote me brainly, it really helps, and i hope i helped you.

5 0
3 years ago
In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
2 years ago
Y=-x^2 +78x-512 I need help with this problem
TiliK225 [7]

Answer:

Step-by-step explanation:

7 0
2 years ago
An assistant cook peeled 18 potatoes in 6 minutes. At this rate, how many potatoes can he peel in 50 minutes?
malfutka [58]

Answer:

150 potatoes

Step-by-step explanation:

Since the assistant can peel 18 potatoes in 6 minutes, we know that he can peel \frac{18}{6}=3 potatoes in 1 minute. Therefore, he will be able to peel 3*50=150 potatoes in 50 minutes. Hope this helps!

7 0
3 years ago
Read 2 more answers
What are the next 3 numbers in this pattern of integers -2, -1, -1, 0, -1, 1, -2
sashaice [31]

Answer:

The next 3 numbers to the given pattern of integers is -2,-1,-1,0,-1,1,-2 are 3,-5,8

Step-by-step explanation:

Given pattern of integers is -2,-1,-1,0,-1,1,-2

To find their next 3 numbers of the given pattern :

Let a_{1}=-2

a_{2}=-1

a_{3}=a_{1}-a_{2}

=-2-(-1)

=-2+1

Therefore a_{3}=-1

a_{4}=a_{2}-a_{3}

=-1-(-1)

=-1+1

Therefore a_{4}=0

Similarly we have a_{5}=-1 ,a_{6}=1 ,a_{7}=-2

The general form to the given pattern is

a_{n}=a_{n-2}+a_{n-1}  for n={\{1,2,3,4,5,6,7,8,9,10}\}

Therefore to find the a_{8},a_{9},a_{10}

Put n=8 in a_{n}=a_{n-2}-a_{n-1}

a_{8}=a_{8-2}-a_{8-1}

=a_{6}-a_{7}

=1-(-2)

a_{8}=3

Put n=9 in a_{n}=a_{n-2}-a_{n-1}

a_{9}=a_{9-2}-a_{9-1}

=a_{7}-a_{8}

=-2-(3)

a_{9}=-5

Put n=10 in a_{n}=a_{n-2}-a_{n-1}

a_{10}=a_{10-2}-a_{10-1}

=a_{8}-a_{9}

=3-(-5)

a_{10}=8

Therefore the next 3 numbers are 3,-5,8

4 0
3 years ago
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