We are going to round the number '3'.
Look at the first number to the right of '3', which is '9'.
That number is greater than '5', so you round the '3' to '4', and add three zeros after '4'.
Answer is: 4,000
Answer:
x = -7
Step-by-step explanation:
Simplifying
5x + 130 = 8x + 151
Reorder the terms:
130 + 5x = 8x + 151
Reorder the terms:
130 + 5x = 151 + 8x
Solving
130 + 5x = 151 + 8x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-8x' to each side of the equation.
130 + 5x + -8x = 151 + 8x + -8x
Combine like terms: 5x + -8x = -3x
130 + -3x = 151 + 8x + -8x
Combine like terms: 8x + -8x = 0
130 + -3x = 151 + 0
130 + -3x = 151
Add '-130' to each side of the equation.
130 + -130 + -3x = 151 + -130
Combine like terms: 130 + -130 = 0
0 + -3x = 151 + -130
-3x = 151 + -130
Combine like terms: 151 + -130 = 21
-3x = 21
Divide each side by '-3'.
x = -7
Simplifying
Answer:
1/6
Step-by-step explanation:
there are 6 faces on a dice so there's a 1 in 6 chance that you would roll a 3 on your second go there is still only a 1 out of 6 chance of getting a 5 because there is still 6 numbers you could roll on.
hope this helped
Answer:
5x>0
x
0
Step-by-step explanation:
Is negative 9?
![\sqrt[3]{x + 1} = 2](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%20%2B%201%7D%20%20%3D%202)
Let us cube both sides.
![= > (\sqrt[3]{x + 1} ) ^{3} = {2}^{3}](https://tex.z-dn.net/?f=%20%3D%20%20%3E%20%20%28%5Csqrt%5B3%5D%7Bx%20%2B%201%7D%20%29%20%5E%7B3%7D%20%20%3D%20%20%7B2%7D%5E%7B3%7D%20)
Now, it will be only x + 1.
Transpose 1 to the Right Hand Side.
Now, subtract.
<u>Answer</u><u>:</u>
x = 7
Hope you could understand.
If you have any query, feel free to ask.
