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nataly862011 [7]
3 years ago
6

12 is 1/5 of what number?

Mathematics
2 answers:
Nastasia [14]3 years ago
8 0
60.

12 x 5= 60

Therefore, 12 is 1/5 of 60.
grin007 [14]3 years ago
8 0

Answer:

12 is 1/5 of 60

Step-by-step explanation:

12 x 5 is 60.

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What do 9/2 equal????​
schepotkina [342]

Step-by-step explanation:

\frac{9}{2}  = 4\frac{1}{2}  = 4.5

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Graph the equation by plotting three
andre [41]

Answer:x=−y−1

Step-by-step explanation:Let's solve for x.

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Step 1: Flip the equation.

x+1=−y

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x+1+−1=−y+−1

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Answer:

x=−y−1

6 0
3 years ago
An archway is modeled by the equation y = -2x^2 + 8x. A rod is to be placed across the archway at an angle defined by the equati
DIA [1.3K]
To solve this problem you must apply the proccedure shown below: 

1. You have that the the <span>archway is modeled by the equation y=-2x^2+8x and the angle mentioned in the problem is defined by the equation x−2.23y+10.34=0.
</span>
 2. Therefore, you must susbtitute y=-2x^2+8x into x−2.23y+10.34=0, as below:

 x−2.23(-2x^2+8x)+10.34=0

 3. When you apply the distributive property, you obtain:

 x−2.23(-2x^2+8x)+10.34=0
 x+4.46x^2-17.84x+10.34=0
 4.46x^2-16.84x+10.34=0

 4. When you solve the quadratic equation, you obtain:

 x=3 units

 Therefore, the answer is the option D: D. 3 units.
3 0
4 years ago
Read 2 more answers
In how many years will RS 1200 at the rate of 15 % interest amount to RS 1740 PLS REPLY FAST I NEED YOUR HELP​
olganol [36]

Answer:

Step-by-step explanation:

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6 0
3 years ago
Given the rectangle abcd shown below has a total area of 72. E is in the midpoint of bc and f is the midpoint of dc. What is the
scoray [572]

Refer to the attached image.

Given the rectangle ABCD of length 'l' and height 'h'.

Therefore, CD=AB = 'l' and BC = AD = 'h'

We have to determine the area of triangle AEF.

Area of triangle AEF = Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE

Area of triangle ADF = \frac{1}{2}bh

= \frac{1}{2}(DF \times AD)

= \frac{1}{2}(\frac{l}{2} \times h)

=\frac{lh}{4}

Area of triangle ECF = \frac{1}{2}bh

= \frac{1}{2}(CF \times CE)

= \frac{1}{2}(\frac{l}{2} \times \frac{h}{2})

=\frac{lh}{8}

Area of triangle ABE = \frac{1}{2}bh

= \frac{1}{2}(AB \times BE)

= \frac{1}{2}(l \times \frac{h}{2})

=\frac{lh}{4}

Now, area of triangle AEF =

Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE

= 72 - (\frac{lh}{4} + \frac{lh}{8} + \frac{lh}{4})

= 72 - (\frac{2lh+lh+2lh}{8})

=72 - (\frac{5lh}{8})

=72 - (\frac{5 \times 72}{8})

=\frac{72 \times 8 - (5 \times 72)}{8}

= 27 units

Therefore, the area of triangle AEF is 27 units.

8 0
3 years ago
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