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Licemer1 [7]
4 years ago
11

NEED HELP ASAP In the unit similar triangles and trigonometry, what is “ compass bearings ?”

Mathematics
2 answers:
faust18 [17]4 years ago
8 0

Answer:

What is the difference between constructing a square and constructing a regular hexagon?

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.

The radius of the circle is used for the square construction, but the diameter of the circle is used for the regular hexagon construction.

The square will need two arcs along the circle, but the hexagon will need two arcs above and two arcs below the diameter of the circle.

The square will need six arcs along the circle, but the hexagon will need two arcs above and two arcs below the diameter of the circle.

Step-by-step explanation:

JulsSmile [24]4 years ago
7 0

Answer:

this is what I found "The bearing of a point is the number of degrees in the angle measured in a clockwise direction from the north line to the line joining the centre of the compass with the point. A bearing is used to represent the direction of one point relative to another point."

I can't really make sense of it though...

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4 years ago
The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated b
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Answer:

A task time of 177.125s qualify individuals for such training.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so \mu = 145, \sigma = 25.

The fastest 10% are to be given advanced training. What task times qualify individuals for such training?

This is the value of X when Z has a pvalue of 0.90.

Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when Z = 1.285.

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1.285 = \frac{X - 145}{25}

X - 145 = 32.125

X = 177.125

A task time of 177.125s qualify individuals for such training.

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3 years ago
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Answer:

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Step-by-step explanation:

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