1/4 # hamburger = 16 oz to a pound so 1/4 is 4 oz.
1 doz baseballs (12), 5 oz each
Box = 9 oz.
Total weight = 12x5 = 60 oz. + 9 oz. = 69 oz.
69/16 = 4 lb. 5 oz.
Answer:
A task time of 177.125s qualify individuals for such training.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so
.
The fastest 10% are to be given advanced training. What task times qualify individuals for such training?
This is the value of X when Z has a pvalue of 0.90.
Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when
.
So




A task time of 177.125s qualify individuals for such training.
4 500-60 = 4 440
4 440/38 = 116.8
At most they would be able to invite 116 people to the reception with their budget.
Answer:
c. 6x + 15 = 39
Step-by-step explanation:
hope this helps