Answer:his speed in still air is 6 miles per minute.
the speed of the wind is 1 mile per minute.
Step-by-step explanation:
Let x represent his speed in still air.
Let y represent the speed of the wind.
It takes Jack Frost 5 minutes to fly 35 miles with the wind. This means that his total speed would be x + y
Distance = speed × time
It means that
35 = 5(x + y)
35 = 5x + 5y - - - - - - - - - - -1
It takes him 7 minutes to go 35 miles against the wind. This means that his total speed would be x - y
It means that
35 = 7(x - y)
35 = 7x - 7y - - - - - - - - - - -2
Multiplying equation 1 by 7 and equation 2 by 5, it becomes
245 = 35x + 35y
175 = 35x - 35y
Adding both equations, it becomes
420 = 70x
x = 420/70 = 6
Substituting x = 6 into equation 1, it becomes
35 = 5 × 6 + 5y
35 = 30 + 5y
5y = 35 - 30 = 5
y = 5/5 = 1
Answer:
54 :)
Step-by-step explanation:
Answer:
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Step-by-step explanation:
To simplify and solve this equation we must follow PEMDAS.
P=Parentheses
E=Exponents
M=Multiplication (from left to right)
D=Division (from left to right)
A=Addition
S=Substraction
We begin the process.
10^3=1000
10^7=10000000
New equation looks like this:
7.2*1000/1.8*10000000
We then multiply
7.2*1000= 7200
7200/1.8=4000
4000*10000000= 40000000000
<em>So our final answer is 40000000000.</em>
Hope this helps!
P.S. I forgot this was scientific notation and I solved it a different way. But both ways give the same answer. Let me know if you want the other method.
Answer:
The perimeter of a quarter of a circle with radius 2 inches is 7.1 inches.
Step-by-step explanation:
Given : A quarter of a circle with radius labeled 2 in.
Quarter of circle means fourth part of a circle (as shown in image by shaded part).
We have to find the perimeter of this shaded quarter of circle.
Perimeter is the sum of the dimension of the given figure.
Perimeter of circle is 
Since, we are given Quarter circle so its perimeter 
Perimeter of given figure = 
Perimeter of given figure = 
Thus, the perimeter of a quarter of a circle with radius 2 inches is 7.1 inches.