Answer:
c+2
Step-by-step explanation:
Answer:
c) skewed to the right.
Step-by-step explanation:
We need to remember that is a distribution is skewed to the right then we have the following condition satisfied:

And if is skewed to the left then we have:
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If the distribution is symmetric we need to satisfy:

For this case since we have most of the values between 200000 and 500000 when we put atypical values like 15000000 that would affect the sample mean and on this case the sample mean would larger than the sample median because the median is a robust measure of central tendency not affected by outliers.
So for this special case we can say that the
. And probably the median would be higher than the mode so then we can conclude that the best answer for this case would be:
c) skewed to the right.
This is a linear function, of the kind y = mx + b
where x is the number of visit, b is the weight when x = 0, and m is the predicted change of weight for every visit.
m = - 4 ounces / visit, which must be converted to pounds (the negative sign indicates that the change is a decrease)
1 lb = 16 ounces = 4 ounces = 0.25 lb
Then m = - 0.25 lb / visit.
Now, for x = 1, y = 126 => 126 = - 0.25(1) + b => b = 126 + 0.25 = 126.25
Then the function is y = 126.25 - 0.25x
Now round to the nearest tenth:
y = 126.3 - 0.3x
Answer: y = 126.3 - 0.3x
Answer:
d=222
Step-by-step explanation: