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2 years ago

Can you do c and d pla

Mathematics

1 answer:

Anna71 [15]2 years ago

7 0

Answer:

c) y = - 2 x +3

d) y = 1/2 x + 1

Step-by-step explanation:

For c) Look for the exression that contains "3" as the y-intercept (the "b" in the form y = m x + b)

The only equation is y = - 2 x +3

For d) try in all equations if replacing x with 2, gives you an answer "2" for y as well.

The only equation that does such is y = 1/2 x + 1

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grin007 [14]

27.22ft

.,..................

9 x

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7 35

9*35= 315

315/7= 27.22ft

5 0

3 years ago

A half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches. Assume that the heights of

Ainat [17]

Answer:

99.5% of all samples of 21 of today's women in their 20's have mean heights of at least 65.86 inches.

Step-by-step explanation:

We are given that a half-century ago, the mean height of women in a particular country in their 20's was 64.7 inches. Assume that the heights of today's women in their 20's are approximately normally distributed with a standard deviation of 2.07 inches.

Also, a samples of 21 of today's women in their 20's have been taken.

Let $\bar X$ = sample mean heights

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean height of women = 64.7 inches

$\sigma$ = standard deviation = 2.07 inches

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample of 21 of today's women in their 20's have mean heights of at least 65.86 inches is given by = P( $\bar X$ $\geq$ 65.86 inches)

P( $\bar X$ $\geq$ 65.86 inches) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{65.86-64.7}{\frac{2.07}{\sqrt{21} } }$ ) = P(Z $\geq$ -2.57) = P(Z $\leq$ 2.57)

= 0.99492 or 99.5%

The above probability is calculated by looking at the value of x = 2.57 in the z table which has an area of 0.99492.

Therefore, 99.5% of all samples of 21 of today's women in their 20's have mean heights of at least 65.86 inches.

3 0

3 years ago

How do you do fraction ,like 20 on top line then 30 on bottom ,I was bad art math sorry please explaine to my daughter so she ca

telo118 [61]

Alright, so since I don't have an example question, I will make one up.

there are 8 coins in total. there are 6 dimes. What is the fraction of dimes to coins.

you would put the amount of dimes on the top and the total on the bottom.

Answer: 6/8 which can be simplified to 3/4

Or another Example:

There are 12 pieces in the pizza. Billy took 4. what is the fraction of the slices left.

it would be 4-12= 8

Answer: 8/12 which can be simplified to 4/6 and then to 2/3

Hope that helped.

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2 years ago

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You scored a 91 on a test with bonus points. you got 4 bonus points how many points did you score before the bonus points

Alex Ar [27]

You need to subtract the bonus points form the final score: 91-4=87

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3 years ago

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DA−2qA=B^3 Solve for A

a_sh-v [17]

Answer: