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3 years ago

Today 67 students are going on a

Mathematics

2 answers:

Agata [3.3K]3 years ago

6 0

Answer: 1.34

Step-by-step explanation:

Fudgin [204]3 years ago

4 0

I know this is a little weird but the answer is 1.34 buses.

You need to divide 67 by 50.

Hope I helped and good luck!

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What is the rate of change of the function shown in the table below

weqwewe [10]

Answer: -3

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Write an explicit formula for the geometric sequence below and use it to find the 9th term. 256, 64, 16, 4, . . .

Nastasia [14]

im doing this problem right now---

ok so a1=256 a2=64 a3=15 a4=4... find a9

the sequence divides by 1/4 every term

an=a1*r^n-1

an=(256)*(1/4)^n-1

replace n with 9

A9=(256)*(1/4)^9-1

A9=(256)*(1/4)^8

=(256)*(1/4)

A9=64^8

1/256 or a9= 0.00390625

7 0

2 years ago

Myra owns a car service that charges a $5 flat rate and an additional $0.50 per mile, which is represented by the equation y = 0

klasskru [66]

Just substitute
0.5(30)+5 =20

6 0

3 years ago

Read 2 more answers

Isabel’s car gets 33.5 miles per gallon. Her gas tank holds 15.1 gallons of gas how many miles can Isabel drive on a full tank o

bagirrra123 [75]

Isabel can drive 505.85 miles with a gas tank that holds 15.1 gallons of gas

Solution:

Given that, Isabel’s car gets 33.5 miles per gallon

Her gas tank holds 15.1 gallons of gas

To find: Number of miles can Isabel drive on a full tank of gas

Let "x" be the miles drive with 15.1 gallons of gas

From given,

1 gallon = 33.5 miles

15.1 gallon = x miles

This forms a proportion and we can solve the sum by cross multiplying

$1 \times x = 15.1 \times 33.5\\\\x = 505.85$

Thus Isabel can drive 505.85 miles on a full tank of gas

6 0

3 years ago

I need help. this is the problem x^2/3+10=7x^1/3

Arlecino [84]

$\it x^{\frac{2}{3}}+10=7x^{\frac{1}{3}} \Leftrightarrow (x^{\frac{1}{3}})^2-7x^{\frac{1}
 {3}} +10=0 
\\\;\\
We\ note\ x^{\frac{1}{3}} =t \ \ and \ the \ equation \ will \ be:
\\\;\\
t^2-7t+10 = 0 \Leftrightarrow t^2 -2t-5t+10=0 \Leftrightarrow t(t-2) -5(t-2)=0$

$\it \Leftrightarrow (t-2)(t-5)=0 
\\\;\\
t-2=0 \Rightarrow t=2 \Rightarrow x^{\frac{1}{3}}=2 \Rightarrow (x^{\frac{1}{3}})^3 =2^3 \Rightarrow x = 8
\\\;\\
t-5=0 \Rightarrow t=5 \Rightarrow x^{\frac{1}{3}}= 5 \Rightarrow (x^{\frac{1}{3}})^3 = 5^3 \Rightarrow x = 125$

S = {8; 125}

7 0

3 years ago