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MatroZZZ [7]
3 years ago
14

Find an equation of a line that comes close to the points listed in the table.

Mathematics
1 answer:
sergey [27]3 years ago
3 0
y=x+2\\x=6\to y=6+2=8\\x=10\to y=10+2=12\\x=12\to y=12+2=14\\x=16\to y=16+2=18\\x=18\to y=18+2=20\\-----------------------\\y=x+3\\x=6\to y=6+3=9\\x=10\to y=10+3=13\\x=12\to y=12+3=15\\x=16\to y=16+3=19\\x=18\to y=18+3=21\\-----------------------\\Answer:y=x+1.5
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Suppose you are asked to find the area of a rectangle that is 2.1-cm wide by 5.6-cm long. Your calculator answer would be 11.76
IRINA_888 [86]

Answer:

The area of the rectangle is 12 cm² (to two significant figures)

Step-by-step explanation:

To determine the area of a rectangle that is 2.1-cm wide by 5.6-cm long,

The area of a rectangle is given by

Area = l × w

where l is the length

and w is the width

From the question,

l = 5.6 cm

and w = 2.1 cm

Hence, Area of the given rectangle will be

Area = 5.6 cm × 2.1 cm

Area = 11.76 cm²

Now, we will convert the answer to two significant figures

Then,

Area = 12 cm²

Hence, the area of the rectangle is 12 cm² (to two significant figures)

3 0
3 years ago
How do u round 33 and 89 to estimate their sum
Zolol [24]
33 would round down. (30)

This is because the second 3 is smaller than 5 and when your rounding, if number your rounding is smaller then 5 you will round down

89 would round up. (90)

This is because the 9 is larger than 5 which means you would round up.


Please mark brainlies
6 0
3 years ago
Using traditional methods it takes 92 hours to receive an advanced flying license. A new training technique using Computer Aided
DanielleElmas [232]

Answer:

The value of the test statistic is z = 1.39.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

Step-by-step explanation:

Using traditional methods it takes 92 hours to receive an advanced flying license.

This means that at the null hypothesis, it is tested if the mean is of 92, that is:

H_0: \mu = 92

Test if there is evidence that the technique lengthens the training time

At the alternative hypothesis, it is tested if the mean is more than 92, that is:

H_1: \mu > 92

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

92 is tested at the null hypothesis:

This means that \mu = 92

A researcher used the technique on 70 students and observed that they had a mean of 93 hours. Assume the population variance is known to be 36.

This means that n = 70, X = 93, \sigma = \sqrt{36} = 6

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{93 - 92}{\frac{6}{\sqrt{70}}}

z = 1.39

The value of the test statistic is z = 1.39.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 93, which is 1 subtracted by the p-value of z = 1.39.

Looking at the z-table, z = 1.39 has a p-value of 0.9177.

1 - 0.9177 = 0.0823.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

8 0
3 years ago
What is the standard numeral for nineteen million,seven hundred thousand
ivolga24 [154]
19,700,000 because 19 million is 19,000,000 and 700,000 is 700,000 add thise together and you get 19,700,000
7 0
3 years ago
Give brainly plsssss help meeee
irina1246 [14]

Answer:

the answer is 48, or the second choice B

Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
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