Question

What is an equation of the line that passes through the points (-6, -8)and (-3, -3)? Put your answer in fully reduced form.

Answer 1

Answer:

The equation of the line that passes through the points (-6, -8)and (-3, -3) is

5 x - 3 y + 6 =0

Step-by-step explanation:

Step(i):-

Given points are ( -6 ,-8) and ( -3 ,-3)

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2} - x_{1} } = \frac{-3+8}{-3+6} = \frac{5}{3}$

Step(ii):-

Slope -point form

$y-y_{1} =m(x-x_{1} )$

$y-(-8) =\frac{5}{3} (x-(-6) )$

cross multiplication, we get

3(y +8 ) = 5(x+6)

3 y +24 = 5 x +30

5 x - 3 y +30 -24 =0

5 x - 3 y + 6 =0

Final answer:-

The equation of the line that passes through the points (-6, -8)and (-3, -3) is

5 x - 3 y + 6 =0