300 / 0.06 = 5000
answer <span>Three hundred is 6 percent of 5,000
</span>
Let
x-------> the first number
y------> the second number
we know that
equation 
equation 
substitute equation 1 in equation 2
using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
I believe the answer could be
h = -16t^2 + 32t + 12
---------------------------
t<span />
Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
