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DIA [1.3K]
3 years ago
15

5 ( c+ 2) = -20 12a + 5 - 8a = -1 m - 3 - 6m = -27 please solve

Mathematics
1 answer:
mel-nik [20]3 years ago
5 0

c = -6

a = -3/2

m = -24/5

Step-by-step explanation:

<h2>#1</h2>

5(c + 2) = -20

5c + 10 = -20

5c = -20 - 10

5c = -30

<u>c = -6</u>

<h2>#2</h2>

12a + 5 - 8a = -1

4a + 5 = -1

4a = -1 - 5

4a = -6

a = (-6)/4

<u>a = -3/2</u>

<h2>#3</h2>

m - 3 - 6m = -27

-5m - 3 = -27 → (times -1)

5m + 3 = 27

5m = 27 - 3

5m = 24

<u>m = 24/5</u>

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I need help with letters (D) and (E). My model equation from letter (C) is: P = -55/4 t+ 340.
IceJOKER [234]

Answer:

(a) The two ordered pairs are (0 , 340) and (4 , 285)

(b) The slope is m = -55/4

The slope means the rate of decreases of the owl population was 55/4

per year (P decreased by 55/4 each year)

(c) The model equation is P = -55/4 t + 340

(d) The owl population in 2022 will be 216

(e)  At year 2038 will be no more owl in the park

Step-by-step explanation:

* Lets explain how to solve the problem

- The owl population in 2013 was measured to be 340

- In 2017 the owl population was measured again to be 285

- The owl population is P and the time is t where t measure the numbers

 of years since 2013

(a) Let t represented by the x-coordinates of the order pairs and P

   represented by the y-coordinates of the order pairs

∵ t is measured since 2013

∴ At 2013 ⇒ t = 0

∵ The population P in 2013 was 340

∴ The first order pair is (0 , 340)

∵ The time from 2013 to 2013 = 2017 - 2013 = 4 years

∴ At 2017 ⇒ t = 4

∵ The population at 2017 is 285

∴ The second order pair is (4 , 285)

* The two ordered pairs are (0 , 340) and (4 , 285)

(b) The slope of any lines whose endpoints are (x1 , y1) and (x2 , y2)

     is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

∵ (x1 , y1) is (0 , 340) and (x2 , y2) is (4 , 285)

∴ x1 = 0 , x2 = 4 and y1 = 340 , y2 = 285

∴ m = \frac{285-340}{4-0}=\frac{-55}{4}

* The slope is m = -55/4

∵ The slope is negative value

∴ The relation is decreasing

* The slope means the rate of decreases of the owl population was

  55/4 per year (<em>P decreased by 55/4 each year</em>)

(c) The linear equation form is y = mx + c, where m is the slope and c is

    the value of y when x = 0

∵ The population is P and represented by y

∵ The time is t and represented by t

∴ P = mt + c , c is the initial amount of population

∵ m = -55/4

∵ The initial amount of the population is 340

∴ P = -55/4 t + 340

* The model equation is P = -55/4 t + 340

(d) Lets calculate the time from 2013 to 2022

∵ t = 2022 - 2013 = 9 years

∵ P = -55/4 t + 340

∴ P = -55/4 (9) + 340 = 216.25 ≅ 216

* The owl population in 2022 will be 216

(e) If the model is accurate , then the owl population be be zero after

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∵ P = -55/4 t + 340

∵ P = 0

∴ 0 = -55/4 t + 340

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∴ 55/4 t = 340

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- Divide both sides by 55

∴ t = 24.7 ≅ 25 years

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∵ 2013 + 25 = 2038

* At year 2038 will be no more owl in the park

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Answer:

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Step-by-step explanation:

to reverse the division  meaning the fraction, we multiply 4 by 4:

4 times 4=16

to check, divide:

16/4=4

i hope this helps u pls give a brainliest and a thx ;)

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