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svlad2 [7]
2 years ago
6

The area has to be in metres^2

Mathematics
1 answer:
Serjik [45]2 years ago
6 0

Answer:

0.6m²

Step-by-step explanation:

Length: 1.2 m

Width: 50cm=0.5m

Area=length×widtg

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A storage bin in the shape of a rectangular prism has a volume of 10x3+9x2+2x.What linear expressions can represent possible dim
Mice21 [21]

Answer:72

Step-by-step explanation:

3 0
3 years ago
Find all the critical points of h(x) = x^3 − 3x^4 and categorize them as local
neonofarm [45]

Answer:

0 is an inflection point

1/4 is a local maximum.

Step-by-step explanation:

To begin with you find the first derivative of the function and get that

h'(x) = 3x^2 - 12x^3

to find the critical points you equal the first derivative to 0  and get that

3x^2 - 12x^3 = 0, x =  0,1/4

To find if they are maximums or local minimums you use the second derivative.

h''(x) = 6x-36x^2

since h''(0) = 0 is neither an inflection point, and since h''(1/4) = -3/4 then 1/4 is a maximum.

6 0
3 years ago
Use the graph to find the factorization of x2 - 6x + 8.
WARRIOR [948]

Answer:

D. (x-2)(x-4)

Step-by-step explanation:

The graph cross the x-axis in points with x-coordinates of 2 and 4

then 2 and 4 are roots of x² - 6x + 8.

4 0
3 years ago
Please help me! Need answers
RSB [31]
Ok, this definition of f is just a bunch of points (4 to be exact).

so if point (a,b) is part of f, then f(a)=b

f(1) is about point (1,0), so f(1)=0.
g(1) = 1 (due to point (1,1))
g(2/3) = 0
f(2) = 3/4
g(-2) = 3
f(π) = -2

just a lookup once you see what is happening
6 0
3 years ago
Atul has 2/3 lb of candy. Jose has 3/5 lb and Maria has 1/2 lb less then José. How many more pounds of candy does Atul have than
liraira [26]

Given:

Atul has \dfrac{2}{3} lb of candy.

Jose has \dfrac{3}{5} lb of candy.

Maria has \dfrac{1}{2} lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has \dfrac{1}{2} lb less than Jose, therefore

Maria has = \dfrac{3}{5}-\dfrac{1}{2} lb

Maria has = \dfrac{6-5}{10} lb

Maria has = \dfrac{1}{10} lb

Difference between the candies Atul and Maria have.

Difference = \dfrac{2}{3}-\dfrac{1}{10} lb

Difference = \dfrac{20-3}{30} lb

Difference = \dfrac{17}{30} lb

Therefore,  Atul have \dfrac{17}{30} lb of candy more than Maria.

6 0
3 years ago
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