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MakcuM [25]
3 years ago
14

What is the value of log5 625? Help me plz

Mathematics
2 answers:
alisha [4.7K]3 years ago
7 0

Answer: 4

Step-by-step explanation:

Just took the test

OLga [1]3 years ago
3 0

Answer: The answer is 4.

log5 (625) can be interpreted as, "5to what power is equal to 625?

"Since 54=625,log5(625)=4

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Write 0.397 as a fraction in simplest form.
e-lub [12.9K]

Answer:

397/1000

Step-by-step explanation:

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7 0
2 years ago
1. Show your work to simplify the expression 0.5(8a +6b) a + 4b​
Anna11 [10]

Answer:

Using distribute property

0.5(8a)(a) + 0.5(6b)(a) + 4b

4a^2 + 3ab + 4b

Step-by-step explanation:

6 0
2 years ago
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Which is equivalent to sin^-1(tan(pi/4)) ? Give your answer in radians.
aleksklad [387]
We are to find the value of sin^{-1}(tan( \frac{ \pi }{4}))

First we evaluate tan(π/4). The value of tan(π/4) is 1. 

So, 

sin^{-1}(tan( \frac{ \pi }{4})) =sin^{-1} (1)

sin(π/2) = 1
So,
sin^{-1}(1)= \frac{ \pi }{2}

Thus, we can write:

sin^{-1}(tan( \frac{ \pi }{4}))= \frac{ \pi }{2} radians.

So, the answer to this question is π/2 radians.
6 0
3 years ago
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amirah ,who is at a point P ,observes a boat at pont B 1200m from P in direction 047 degrees. The boat is moving due north of B
Luda [366]

Answer:

  about 2.81 km/h

Step-by-step explanation:

It can be useful to draw a diagram.

The lines pointing to due north from points B and P are parallel, so the angle BCP and the bearing of point C from P are the same, 30°. The angle BPC will be the difference of bearings of B and C at P, so is 47-30=17°. This is enough information to solve the triangle using the Law of Sines:

  PB/sin(C) = CB/sin(P)

  CB = PB·sin(P)/sin(C) = (1200 m)·sin(17°)/sin(30°) ≈ 701.7 m

The speed of the boat is then ...

  x = distance/time = (0.7017 km)/(1/4 h) = 2.8068 km/h

6 0
3 years ago
Hi I need help with these questions rn, ASAP!
UkoKoshka [18]

i believe the answer is concave

6 0
3 years ago
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