Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since
<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0
and
<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0
it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.
Answer:
18
Step-by-step explanation:
F(10)=3((10)-4) = 18
Answer:
the answer is parallel lines
You can do 5+5+10, 6+6+8, 9+9+2, 4+4+12, 3+3+14, 2+2+16, 1+1+18. I believe these are all of them, so there are 7 ways.
Answer: Never true.
Step-by-step explanation: Distribute the numbers: 4 times x is 4x, 4 times 3 is 12. Then you have the equation: -x+4x +12 = -12. Now, choose a random number, maybe -4. A negative plus a negative cancels out so you are left with 4-16(Because you distribute the number) +12 = -12. 4-16 is -12. -12 plus 12 equals 0.
