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3 years ago

What are the values of x and y if this equation is true? 22(x + yi) + (28 + 4i) 72 – 62i

Mathematics

1 answer:

ASHA 777 [7]3 years ago

8 0

Answer:

x = 2

y = -3

Step-by-step explanation:

The given equation is,

22(x + yi) + (28 + 4i) = 72 - 62i

By solving this equation further,

22x + 22yi + 28 + 4i = 72 - 62i

(22x + 28) + (22y + 4)i = 72 - 62i

Now both the sides of the equation is in the form of complex number,

By comparing real and imaginary parts given on both the sides,

22x + 28 = 72

22x = 72 - 28

22x = 44

x = 2

22y + 4 = -62

22y = -62 - 4

22y = -66

y = -3

Therefore, x = 2 and y = -3 are the values for which the given equation is true.

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Step-by-step explanation:

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babymother [125]

Answer:

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Steps below

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

95+r=2736−2

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Step 2: Subtract 95 from both sides.

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Hope this helps.

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