Step 1: Find f'(x):
f'(x) = -6x^2 + 6x
Step 2: Evaluate f'(2) to find the slope of the tangent line at x=2:
f'(2) = -6(2)^2 + 6(2) = -24 + 12 = -12
Step 3: Find f(2), so you have a point on y=f(x):
f(2) = -2·(2)^3 + 3·(2)^2 = -16 + 12 = -4
So, you have the point (2,-4) and the slope of -12.
Step 4: Find the equation of your tangent line:
Using point-slope form you'd have: y + 4 = -12 (x - 2)
That is the equation of the tangent line.
If your teacher is picky and wants slope-intercept, solve that for y to get:
y = -12 x + 20
Answer:
Standard deviation, means, skewness and kurtosis.
Step-by-step explanation:
Two normal curves may be same but they have different means, standard deviation and skewness. There can be different standard deviation for two curves and there is difference in skewness.
Answer:
the square root of 20 could be between 4 and 5 OR -4 and -5.
Step-by-step explanation:
plus or minus 4 squared is 16 and plus or minus 5 squared is 25. finally, 20 is between 16 and 25.
Answer:
645320
Step-by-step explanation:
Given: 6_5_2_
If a multiplication sign is placed between the second and third digit, and an equal sign is placed between the third and fourth digit, then
6_ × 5 = _2_
The passcode contains 6 DIFFERENT digits, so we know the missing numbers cannot be 6, 5, or 2.
So, do a trial and error session of multiplying 5 by numbers it could possibly be (60, 61, 63, 64, 67, 68, 69).
64 × 5 = 320. It is the only equation that is both correct and matches the digits given, so the missing digits are 4, 3, and 0. Barry's passcode is 645320.
Answer:
A system has infinitely many solutions when it is consistent and the number of variables is more than the number of nonzero rows in the rref of the matrix. For example if the rref is ��has solution set (4-3z, 5+2z, z) where z can be any real number.
