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3 years ago

Simplify the expression. 24x + 32 + 4x + 3

Mathematics

2 answers:

Firdavs [7]3 years ago

8 0

Answer:

28x+35

Step-by-step explanation:

24x+4x= 28x

32+3=35

28x+35

Pavlova-9 [17]3 years ago

6 0

Answer:

28x + 35

Step-by-step explanation:

add alike terms

24x + 4x = 28x

and

32 + 3 = 35

Make sure when simplify other expressions that you watch what is a negative and what is a positive! Now go onward and become the top of your math class!!! I believe in you!

You might be interested in

Using 7 four times and 1 one time getting to 100

777dan777 [17]

Answer:

So the answer is $(7+\frac{1}{7} )\times (7+7)=100$

Step-by-step explanation:

Given,

Using $7$ four times and $1$ one time getting to $100$

If we are write this way then easily get the answer;

$(7+\frac{1}{7} )\times (7+7)$

Add together $7+\frac{1}{7}$ by making a common denominator of $7$ and also add $(7+7)$ in the second set of parenthesis to yield $14$

$(\frac{49+1}{7} )\times 14$

$\frac{50}{7} \times 14$

$50\times 2$ (By Cross-reduce and multiply the fractions)

$100$

∴ $(7+\frac{1}{7} )\times (7+7)=100$

4 0

3 years ago

A farmer has the same number of chickens, cows and goats. Together, all these animals have 210 legs. How many chickens live on t

Ulleksa [173]

Answer:

Step-by-step explanation:

Chickens - 2x

cows - 4x

goats = 4x

2x+4x+4x+210

10x=210

x=21

CHECK:

21 chickens = 42 legs

21 cows = 84 legs

21 goats = 84 legs

42+84+84=210 legs

3 0

2 years ago

Read 2 more answers

6-4x=6x-8x+8 find the value of x

ad-work [718]

Answer:

x = -1

Step-by-step explanation:

6 − 4x = 6x − 8x + 8

Combine 6x and −8x to get −2x.

6 − 4x = −2x + 8

Add 2x to both sides.

6 − 4x + 2x = 8

Combine −4x and 2x to get −2x.

6 − 2x = 8

Subtract 6 from both sides.

−2x = 8 − 6

Subtract 6 from 8 to get 2.

−2x = 2

Divide both sides by −2.

$x = \frac{2}{-2}$

Divide 2 by −2 to get −1.

$x = 1$

Hope this helps and have a great day! =D

7 0

2 years ago

Read 2 more answers

The functions f (theta) and g (theta) are sine functions, where f (0) equals g (0) equals 0.The amplitude of f (theta) is twice

777dan777 [17]

If period of $f(\theta)$ is one-half the period of $g(\theta)$ and
 $g(\theta)$ has a period of 2π, then $T_{g} =2T_{f}=2 \pi$ and $T_{f}= \pi$ .

To find the period of sine function $f(\theta)=asin(b\theta+c)$ we use the rule $T_{f}= \frac{2\pi}{b}$ .

f is sine function where f (0)=0, then c=0; with period $\pi$ , then $f(\theta)=asin 2\theta$ , because $T_{f}= \frac{2 \pi }{2} = \pi$ .

To find a we consider the condition $f( \frac{ \pi }{4} )=4$ , from where $asin2* \frac{\pi}{4} =a*sin \frac{ \pi }{2} =a=4$ .

If the amplitude of $f(\theta)$ is twice the amplitude of $g(\theta)$ , then $g(\theta)$ has a product factor twice smaller than $f(\theta)$ and while period of $g(\theta)$ is 2π and g(0)=0, we can write $g(\theta)=2sin\theta$ .

8 0

3 years ago

How to know if a function is periodic without graphing it ?

zhenek [66]

A function $f(t)$ is periodic if there is some constant $k$ such that $f(t+k)=f(k)$ for all $t$ in the domain of $f(t)$ . Then $k$ is the "period" of $f(t)$ .

Example:

If $f(x)=\sin x$ , then we have $\sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x$ , and so $\sin x$ is periodic with period $2\pi$ .

It gets a bit more complicated for a function like yours. We're looking for $k$ such that

$\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5$

Expanding on the left, you have

$\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2$

and

$1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5$

It follows that the following must be satisfied:

$\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}$

The first two equations are satisfied whenever $k\in\{0,\pm4,\pm8,\ldots\}$ , or more generally, when $k=4n$ and $n\in\mathbb Z$ (i.e. any multiple of 4).

The second two are satisfied whenever $k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}$ , and more generally when $k=\dfrac{10n}7$ with $n\in\mathbb Z$ (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when $k$ is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

$\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2$

$\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5$

More generally, it can be shown that

$f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))$

is periodic with period $\mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n)$ .

4 0

3 years ago