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Hatshy [7]
3 years ago
7

Simplify the expression. 24x + 32 + 4x + 3

Mathematics
2 answers:
Firdavs [7]3 years ago
8 0

Answer:

28x+35

Step-by-step explanation:

24x+4x= 28x

32+3=35

28x+35

Pavlova-9 [17]3 years ago
6 0

Answer:

28x + 35

Step-by-step explanation:

add alike terms

24x + 4x = 28x

        and

  32 + 3 = 35

Make sure when simplify other expressions that you watch what is a negative and what is a positive! Now go onward and become the top of your math class!!! I believe in you!

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Using 7 four times and 1 one time getting to 100​
777dan777 [17]

Answer:

So the answer is (7+\frac{1}{7} )\times (7+7)=100

Step-by-step explanation:

Given,

Using 7 four times and 1 one time getting to  100

If we are write this way then easily get the answer;

(7+\frac{1}{7} )\times (7+7)

Add together 7+\frac{1}{7} by making a common denominator of  7 and also add (7+7) in the second set of parenthesis to yield 14

(\frac{49+1}{7} )\times 14

\frac{50}{7} \times 14

50\times 2   (By Cross-reduce and multiply the fractions)

100

∴ (7+\frac{1}{7} )\times (7+7)=100

4 0
3 years ago
A farmer has the same number of chickens, cows and goats. Together, all these animals have 210 legs. How many chickens live on t
Ulleksa [173]

Answer:

21

Step-by-step explanation:

Chickens - 2x

cows - 4x

goats = 4x

2x+4x+4x+210

10x=210

x=21

CHECK:

21 chickens = 42 legs

21 cows = 84 legs

21 goats = 84 legs

42+84+84=210 legs

3 0
2 years ago
Read 2 more answers
6-4x=6x-8x+8<br><br> find the value of x
ad-work [718]

Answer:

x = -1

Step-by-step explanation:

6 − 4x = 6x − 8x + 8

Combine 6x and −8x to get −2x.

6 − 4x = −2x + 8

Add 2x to both sides.

6 − 4x + 2x = 8

Combine −4x and 2x to get −2x.

6 − 2x = 8

Subtract 6 from both sides.

−2x = 8 − 6

Subtract 6 from 8 to get 2.

−2x = 2

Divide both sides by −2.

x = \frac{2}{-2}

Divide 2 by −2 to get −1.

x = 1

Hope this helps and have a great day! =D

7 0
2 years ago
Read 2 more answers
The functions f (theta) and g (theta) are sine functions, where f (0) equals g (0) equals 0.The amplitude of f (theta) is twice
777dan777 [17]
If period of f(\theta) is one-half the period of g(\theta) and
<span>g(\theta)  has a period of 2π, then T_{g} =2T_{f}=2 \pi and T_{f}= \pi.
</span>
To find the period of sine function f(\theta)=asin(b\theta+c) we use the rule T_{f}= \frac{2\pi}{b}.
<span /><span />
f is sine function where f (0)=0, then c=0; with period \pi, then f(\theta)=asin 2\theta, because T_{f}= \frac{2 \pi }{2} = \pi. 

To find a we consider the condition f( \frac{ \pi }{4} )=4, from where asin2* \frac{\pi}{4} =a*sin \frac{ \pi }{2} =a=4.

If the amplitude of f(\theta) is twice the amplitude of g(\theta) , then g(\theta) has a product factor twice smaller than f(\theta) and while period of g(\theta)<span> </span> is 2π and g(0)=0, we can write g(\theta)=2sin\theta.






8 0
3 years ago
How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
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