... ... ... ... ... ... ... ... ... ...

I neeed help again fast plss

podryga [215]

Answer:

i think the answer is 7.9373

Step-by-step explanation:

so its the Herons Formula (when you know all 3 sides) so the formula would be

Area = √ p ( p − a ) ( p − b ) ( p − c )

p is half the perimeter

or,

a + b + c

-----------------------------

2

4 0

4 years ago

Read 2 more answers

If you divide -16 into 5 equal parts how much is each part equal to?

LekaFEV [45]

I’m pretty sure it’s B (-3.2) because -16/5=-3.2

3 0

3 years ago

Read 2 more answers

Is this correct???? I will give brainliest

zhenek [66]

$\frac{3}{4} \sqrt{-80}$

Step-by-step explanation:

Given data: $\frac{3}{4} \sqrt{-80}$

We find the equivalent value the expression $\frac{3}{4} \sqrt{-80}$ .

The value –80 can be written as –1 × 16 × 5.

Now, substitute the value of –80 in the given expression.

$\frac{3}{4} \sqrt{-80}=\frac{3}{4} \sqrt{-1 \times 16 \times 5}$

$=\frac{3}{4} \sqrt{-1 \times 4^{2} \times 5}$ (16 is the square number of 4)

$=\frac{3}{4} \times 4 \sqrt{-1 \times 5}$ (Square number can be taken out)

$=3 \sqrt{-1 \times 5}$ (4 in the numerator and denominator are cancel)

Since $\sqrt{-1}=i$ ,

$=3i\sqrt{5}$

So, the expression $\frac{3}{4} \sqrt{-80}$ is equivalent to $3i\sqrt{5}$ .

5 0

3 years ago

A study of long-distance phone calls made from General Electric Corporate Headquarters in Fairfield, Connecticut, revealed the l

Anna [14]

Answer:

a) 0.4452

b) 0.0548

c) 0.0501

d) 0.9145

e) 6.08 minutes or greater

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4.7 minutes

Standard Deviation, σ = 0.50 minutes.

We are given that the distribution of length of the calls is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(calls last between 4.7 and 5.5 minutes)

$P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{4.7 - 4.7}{0.50} \leq z \leq \displaystyle\frac{5.5-4.7}{0.50}) = P(0 \leq z \leq 1.6)\\\\= P(z \leq 1.6) - P(z$

$P(4.7 \leq x \leq 5.5) = 44.52\%$

b) P(calls last more than 5.5 minutes)

$P(x > 5.5) = P(z > \displaystyle\frac{5.5-4.7}{0.50}) = P(z > 1.6)\\\\P( z > 1.6) = 1 - P(z \leq 1.6)$

Calculating the value from the standard normal table we have,

$1 - 0.9452 = 0.0548 = 5.48\%\\P( x > 5.5) = 5.48\%$

c) P( calls last between 5.5 and 6 minutes)

$P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{5.5 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(1.6 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z$

$P(5.5 \leq x \leq 6) = 5.01\%$

d) P( calls last between 4 and 6 minutes)

$P(4 \leq x \leq 6) = P(\displaystyle\frac{4 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(-1.4 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z$

$P(4 \leq x \leq 6) = 91.45\%$

e) We have to find the value of x such that the probability is 0.03.

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 4.7}{0.50})=0.03$

$= 1 -P( z \leq \displaystyle\frac{x - 4.7}{0.50})=0.03$

$=P( z \leq \displaystyle\frac{x - 4.7}{0.50})=0.997$

Calculation the value from standard normal z table, we have,

P(z < 2.75) = 0.997

$\displaystyle\frac{x - 4.7}{0.50} = 2.75\\x = 6.075 \approx 6.08$

Hence, the call lengths must be 6.08 minutes or greater for them to lie in the highest 3%.

8 0

3 years ago

Find the value of x.

storchak [24]

Answer:

Generally, the algebraic expression should be any one of the forms such as addition, subtraction, multiplication, and division. To find the value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to find the result.

Step-by-step explanation:

hope this helps you :)

3 0

4 years ago

Read 2 more answers