Question

How would logx (49) = x look like in exponential form

Answer 1

I'm assuming the given log equation is $\log_{\text{x}}(49) = \text{x}$

If so, then the exponential form is $\text{x}^{\text{x}} = 49$

This is because the general form $\log_{\text{b}}(\text{x}) = \text{y}$ transforms into $\text{y} = \text{b}^{\text{x}}$

For both equations, the 'b' is the base.