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algol13
3 years ago
7

Is this correct???? I will give brainliest

Mathematics
1 answer:
zhenek [66]3 years ago
5 0

$\frac{3}{4} \sqrt{-80}$

Step-by-step explanation:

Given data: $\frac{3}{4} \sqrt{-80}$

We find the equivalent value the expression $\frac{3}{4} \sqrt{-80}$.

The value –80 can be written as –1 × 16 × 5.

Now, substitute the value of –80 in the given expression.

$\frac{3}{4} \sqrt{-80}=\frac{3}{4} \sqrt{-1 \times 16 \times 5}$

       =\frac{3}{4} \sqrt{-1 \times 4^{2} \times 5}  (16 is the square number of 4)

       =\frac{3}{4} \times 4 \sqrt{-1 \times 5}  (Square number can be taken out)

       =3 \sqrt{-1 \times 5} (4 in the numerator and denominator are cancel)

Since\sqrt{-1}=i,

       =3i\sqrt{5}  

So, the expression $\frac{3}{4} \sqrt{-80}$ is equivalent to 3i\sqrt{5}.

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