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sergij07 [2.7K]
3 years ago
10

How to write ax+b=c in terms of x

Mathematics
1 answer:
KonstantinChe [14]3 years ago
6 0
X = (c-b)/a all you got to do is slowly move each letter to the other side of the equals sign, and doing the opposite. eg: +b becomes -b on the other side of the equals sign
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The ratio of boys to girls in Coach Sheppard's class is 3 to 5. There are 20 girls
beks73 [17]

Answer:

umm i am pretty sure it is 20 to 22

Step-by-step explanation:

6 0
3 years ago
Which of the following represents a function?
Lyrx [107]

The image on the left represents a function. The image on the right does not as a function cannot have multiple variables for a single X quantity.

8 0
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How do you write 3,029,251 expand from
Fiesta28 [93]
3,000,000 + 20,000 + 9,000 + 200 + 50 + 1
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The radius of a circular pond is increasing at a constant rate, which can be modeled by the function , where t is time in months
horrorfan [7]

Answer:

B. A(r(t)) = 25πt²

Step-by-step explanation:

Find the completed question below

The radius of a circular pond is increasing at a constant rate, which can be modeled by the function r(t) = 5t where t is time in months. The area of the pond is modeled by the function A(r) = πr². The area of the pond with respect to time can be modeled by the composition . Which function represents the area with respect to time? A. B. C. D.

Given

A(t) = πr²

r(t) = 5t

We are to evaluate the composite expression A(r(t))

A(r(t)) = A(5t)

To get A(5t), we will replace r in A(t) with 5t and simplify as shown

A(5t) = π(5t)²

A(5t) = π(25t²)

A(5t) = 25πt²

A(r(t)) = 25πt²

Hence the composite expression A(r(t)) is 25πt²

Option B is correct.

5 0
3 years ago
Hector invests $800 in an account that earns 6.98% annual interest compounded semiannually. Rebecca invests $1000 in an account
Roman55 [17]
A=P (1+r/n)^nt

A= Total amount invested, P=principal amount, r=Interest rate, n=number of time in a year when the interest is earned (for annual, n=1; for semi-annual, n=2, ...), t = time in years

In the current scenario, case 1, n=2; case 2, n=1 and A1=A2, t1=t2
Therefore,
800(1+0.0698/2)^2t = 1000(1+0.0543/1)t
Dividing by 800 on both sides;
(1+0.0349)^2t = 1.25(1+0.02715)^t
(1.0349)^2t = 1.25(1.02715)^t
Taking ln on both sides of the above equation;
2t*ln (1.0349)= ln 1.25 + t*ln (1.02715)
2t*0.0343 = 0.2231+ t*0.0268
0.0686 t = 0.2231+0.0268 t
(0.0686-0.0268)t = 0.2231
0.0418t=0.2231

t=5.337 years

Therefore, after 5.337 years or 5 years and approximately 4 months, their value of investments will be equal.

This value will be,
A=800(1+0.0698/2)^2*5.337 = $1,153.76
3 0
4 years ago
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