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3 years ago

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Rectangle ABCD is dilated by a scale factor of One-half with a center of dilation at the origin. What are the coordinates of the

image of point B prime?
On a coordinate plane, rectangle A B C D has points (negative 8, 6), (negative 4, 6), (negative 4, 4), (negative 8, 4).

(–2, 3)
(3, –2)
(–8, 12)
(12, –8)

2 answers:

Alex787 [66]3 years ago

7 0

Answer: (–2, 3)

Step-by-step explanation: On Edgenuity!!!!!!

Leviafan [203]3 years ago

6 0

Answer:

The answer is A. (–2, 3)

Step-by-step explanation: Hope this helps :)

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Find the ordered pairs for the x- and y-intercepts of the equation 3x − 2y = 18 and select the appropriate option below.

olasank [31]

<h2>Greetings!</h2>

Answer:

B)

Step-by-step explanation:

Y intercept:

Simply substitute all the x values with 0:

When x = 0:

3(0) - 2y = 18

Move the - 2y over to the other side making it a +2y:

0 = 18 + 2y

Move the +18 over to the other side making it a -18:

-18 = 2y

Divide both sides by 2:

$\frac{-18}{2} = \frac{2y}{2}$

-9 = y

So y intercept is:

<h3> (0 , -9)</h3>

X - intercept:

Simply substitute all the Y's with 0:

3x - 3(0) = 18

3x = 18

Divide both sides by 3:

$\frac{3x}{3} = \frac{18}{3}$

x = 6

So the X intercept is:

<h3>(6 , 0)</h3>

This means that your guess of B is correct.

<h2>Hope this helps! </h2>

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3 years ago

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Compare and contrast the expression 2+x and 2+3

NikAS [45]

Well the first equation has a variable in it while the other one doesn't also the first expression if set equal to 0 is -2 while the other one is 5

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3 years ago

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Please help due soon

uysha [10]

Answer:

the answer is (x,y)=(-2,-3)

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In a young single person's monthly budget, $150 is spent on food, $175 is spent on housing, and $175 is spend on other items. Su

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Step-by-step explanation:

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3 years ago

Solve the equations by substitution method: A. 2x-y-3=0 and 3x+4y=65.

PSYCHO15rus [73]

Step-by-step explanation:

$\sf 2x-y-3=0\dots \dots (1)$

$\sf 3x+4y=65 \\ \implies\sf 3x+4y-65=0 \dots\dots(2)$

from eq (1)

${:}\longrightarrow$ $\sf 2x-y-3=0$

${:}\longrightarrow$ $\sf 2x-3=y$

${:}\longrightarrow$ $\sf y=2x-3 \dots\dots(3)$

Substitute the value in eq(2)

${:}\longrightarrow$ $\sf 3x+4y-65=0$

${:}\longrightarrow$ $\sf 3x +4 (2x-3)-65=0$

${:}\longrightarrow$ $\sf 3x+8x-12-65=0$

${:}\longrightarrow$ $\sf 11x-77=0$

${:}\longrightarrow$ $\sf 11x=77$

${:}\longrightarrow$ $\sf x={\dfrac {77}{11}}$

${:}\longrightarrow$ $\sf x=7$

Substitute the value in eq (3)

${:}\longrightarrow$ $\sf y=2x-3$

${:}\longrightarrow$ $\sf y=2 (7)-3$

${:}\longrightarrow$ $\sf y=14-3$

${:}\longrightarrow$ $\sf y=11$

$\therefore$ ${\underline{\boxed{\bf (x,y)=(7,11)}}}$

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2 years ago