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Colt1911 [192]
3 years ago
6

Two lines meet at a point that is also the vertex of an angle; the measurement of ∠

Mathematics
1 answer:
IgorC [24]3 years ago
6 0

Answer:

<em>x = 30°, and y = 46°</em>

Step-by-step explanation:

If we take a look at the attachment below, we will find x = 30°, and y = 46°;

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Write an equation of the line that passes through (4,2) and is perpendicular to the line y=−13x+1.
7nadin3 [17]

Answer:

y=x-2

Step-by-step explanation:

This slope goes through the point and is perpendicular to y=-13x+1

Hope this helped

4 0
3 years ago
What is the y coordinate in the solution for the system of linear equations below
Natali5045456 [20]

Answer:

y=6

Step-by-step explanation:

use elimination by making the ys opposite in value and eliminating them from the equation so there is only variable:

-3x+2y=6

2(4x-y=2)

-3x+2y=6

8x-2y=4

Combine like terms and divide by 5 on both sides.

5x=10

x=2

Plug x in to find y:

4(2)-y=2

8-y=2

y=6

5 0
3 years ago
I don't know who needs to hear this but I wanted to hopefully reach out to someone.
lora16 [44]

Answer:

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Step-by-step explanation:

8 0
3 years ago
sid and Jill hiked 4 1/8 miles in the morning and 1 1/7 miles in the afternoon.how many times as far did they hike in the mornin
mote1985 [20]
Your answer is ..
First,
we have to turn our mixed fractions into an improper fraction.
=4 1/8 which is 33/8(4 x 8 + 1).

Our next mixed fraction,
we have 1 1/7 which is 8/7(1 x 7 + 1).

Now, we have the get the same denominator in order to subtract.
SO, both 8 and 7 goes in to 56. So we multiply both mixed fractions to get the same denominator.
(Tip: what ever you do to do numerator, you do to the denominator; and the other way around).
33/8 : 33*7=231 and our denominator, 8*7=56
So our improper fraction now,
231/56

Our next fraction 8/7,
7*8= 56 and our numerator 8*8=64.
=64/56

So, now we subtract.
231-64= 167 and our common denominator. 167/56

Now we divide 167 by 56 which is 2 and remainder is 55.
So, you should end up with a mixed fraction, 2 55/56.

7 0
3 years ago
Fifty pro-football rookies were rated on a scale of 1 to 5, based on performance at a training camp as well as on past performan
son4ous [18]

Answer:

(a-1) 22 rookies receiving a rating of 4 or better.

(a-2) 14 rookies received a rating of 2 or worse.

(b-1) Constructed below in explanation.

(b-2) 8% of total rookies received a rating of 5.

Step-by-step explanation:

We are provided the rating of Fifty pro-football rookies on a scale of 1 to 5 based on performance at a training camp as well as on past performance.

The frequency distribution constructed is given below:

 Rating          Frequency

     1                       4

     2                     10       where ranking of 1 indicate a poor prospect whereas

     3                     14         ranking of 5 indicate an excellent prospect.

     4                     18

     5                      4

(a-1) Rookies receiving a rating of 4 or better = Rating of 4 + Rating of 5

       So, by seeing the frequency distribution 18 rookies received a rating of

         4 and 4 rookies received a rating of 5.

Hence, Rookies receiving a rating of 4 or better = 18 + 4 = 22 rookies.

(a-2) Number of rookies received a rating of 2 or worse = Rating of 2 +

                                                                                                 Rating of 1

     So, by seeing the frequency distribution 10 rookies received a rating of

      2 and 4 rookies received a rating of 1.

Hence, Rookies receiving a rating of 2 or worse = 10 + 4 = 14 rookies.

(b-1) Relative Frequency is calculated as = Each frequency value /

                                                                         Total Frequency

   Rating        Frequency(f)        Relative Frequency

     1                       4                          4 / 50 = 0.08

     2                     10                         10 / 50 = 0.2

     3                     14                          14 / 50 = 0.28

     4                     18                          18 / 50 = 0.36

     5                   <u>   4    </u>                       4 / 50  = 0.08

                     \sum f<u>= 50 </u>                

Hence, this is the required relative frequency distribution.

(b-2) To calculate what percent received a rating of 5 is given by equation :

            <em>  x% of 50 = 4 </em> {Here 4 because 4 rookies received rating of 5}

         x = \frac{4*100}{50} = 8% .

Therefore, 8% of total rookies received a rating of 5.

5 0
4 years ago
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