Answer:
what r the options
Step-by-step explanation:
Answer:
Option D that is y=-2(x+1) is the correct choice.
Explanation:
Given equation:
We have to find another equation which has only one solution.
Standard form of equation:
![1.a_1x+b_1y+c_1=0](https://tex.z-dn.net/?f=1.a_1x%2Bb_1y%2Bc_1%3D0)
![2.a_2x+b_2y+c_2=0](https://tex.z-dn.net/?f=2.a_2x%2Bb_2y%2Bc_2%3D0)
Condition for one solution.
![\frac{a_1}{a_2} \neq \frac{b_1}{b_2}](https://tex.z-dn.net/?f=%5Cfrac%7Ba_1%7D%7Ba_2%7D%20%5Cneq%20%5Cfrac%7Bb_1%7D%7Bb_2%7D)
We have to arrange other equation in the form of ![ax+by+c=0](https://tex.z-dn.net/?f=ax%2Bby%2Bc%3D0)
Mark all the options as a,b,c and d.
![a.\ 2x+1-y=0](https://tex.z-dn.net/?f=a.%5C%202x%2B1-y%3D0)
![b.\ 2x-2-y=0](https://tex.z-dn.net/?f=b.%5C%202x-2-y%3D0)
![c.\ 2x-4-y=0](https://tex.z-dn.net/?f=c.%5C%202x-4-y%3D0)
![d.-2x-2-y=0](https://tex.z-dn.net/?f=d.-2x-2-y%3D0)
Now from the above options we can see that option
are not providing the desired result.
So
can be obtained from the last option.
As
![\frac{a_1}{a_2} \neq \frac{b_1}{b_2} ,\frac{2}{-2} \neq \frac{-1}{-1} ,-1\neq 1](https://tex.z-dn.net/?f=%5Cfrac%7Ba_1%7D%7Ba_2%7D%20%5Cneq%20%5Cfrac%7Bb_1%7D%7Bb_2%7D%20%2C%5Cfrac%7B2%7D%7B-2%7D%20%5Cneq%20%5Cfrac%7B-1%7D%7B-1%7D%20%2C-1%5Cneq%201)
Option D that is
is the equation from where we can obtained only one solution.
50 is a composite number. 50 = 1 x 50; 2 x 25; or 5 x 10. Factors of 50: 1, 2, 5, 10, 25, 50.
Prime factorization: 50 = 2 x 5 x 5.
Not proportional hope that helps
Answer:
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