F(x) = x + 2
when x = 1, f(1) = 1 + 2 = 3
Therefore range for x ≠ 1 is y ≠ 3.
Answer:
0.5 chance
1/2 chance
Reason:
Half the bag is peanuts therefore there is half a chance you will pick one out
Answer:
12
Step-by-step explanation:
Use the relation between 3 is to 51
eventually... you will
Answer:
x = 7 is repeated twice.
Hence, there is NO MORE unique input. We can not have repeated inputs.
Thus, the relation is NOT a function.
Step-by-step explanation:
Given the relation
- {(6, 8), (7, 10), (7, 12), (8, 16),
(10, 16)}
We know that a relation is a function that has only one output for any unique input.
As the inputs or x-values of the relations are:
at x = 6, y = 8
at x = 7, y = 10
at x = 7, y = 12
at x = 8, y = 16
at x = 10, y = 16
If we closely observe, we can check that there is a repetition of x values.
i.e. x = 7 is repeated twice.
Hence, there is NO MORE unique input. We can not have repeated inputs.
Thus, the relation is NOT a function.
