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alexandr402 [8]
3 years ago
6

A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between

times of maximum brightness is 4.2 days. The average brightness of this star is 3.0 and its brightness changes by ±0.25. In view of these data, the brightness of the star at time t, where t is measured in days, has been modeled by the function B(t) = 3.0 + 0.25 sin 2πt 4.2 . (a) Find the rate of change of the brightness after t days. dB dt =
Mathematics
1 answer:
victus00 [196]3 years ago
4 0

Answer:

a) \frac{dB}{dt} = \frac{5\pi}{4.2} \cdot \cos \left(2\pi\cdot \frac{t}{4.2} \right), b) \frac{dB}{dt}\approx 5.595

Step-by-step explanation:

a) The rate of change of the brightness of the Cepheid can be determined by deriving the function in time:

\frac{dB}{dt} = \left(\frac{2\pi}{4.2} \right)\cdot 0.25\cdot \cos (2\pi\cdot \frac{t}{4.2})

\frac{dB}{dt} = \frac{5\pi}{4.2} \cdot \cos \left(2\pi\cdot \frac{t}{4.2} \right)

b) The rate of increase after one day is:

\frac{dB}{dt} = \frac{5\pi}{4.2} \cdot \left(2\pi \cdot \frac{1}{4.2} \right)

\frac{dB}{dt}\approx 5.595

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Answer:

The answer to your question is  c = \sqrt{2593}

Step-by-step explanation:

Data

right triangle

short leg = 17 cm

long leg = 48 cm

hypotenuse = ?

Process

-Use the Pythagorean theorem to find the answer

              c² = a² + b²

c = hypotenuse

a = short leg = 17 cm

b = long leg = 48 cm

- Substitution

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-Simplification

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-Result

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