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Andrew [12]
3 years ago
7

What is three tenths times two and five sixths?

Mathematics
2 answers:
Alchen [17]3 years ago
4 0
17 over 20 or .85 because u change the 2 and 5 sixths to a improper fraction and the multiply.
Virty [35]3 years ago
3 0
To multiply fraction do top x top and bottom x bottom 
so convert 2 \frac{5}{6} into \frac{17}{6}
then do \frac{3}{10} * \frac{17}{6} =  \frac{3*17}{10*6} =  \frac{51}{60} =  \frac{17}{20}

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The ordered pair (3,9) is a solution to the system of
nadya68 [22]

Answer:

(2,7) is not a solution to the given system of equations.

Step-by-step explanation:

Given system of equation is:

2x + 3 = y

2x + y = 15

To check whether (2,7) is solution to this system or not, we will put x=2 and y=7 in both equations.

Putting x=2 and y=7 in Eqn 1

2(2) + 3 = 7

4 + 3 = 7

7 = 7

Thus the ordered pair satisfies the equation

Putting x=2 and y=7 in Eqn 2

2(2) + 7 = 15

4 + 7 = 15

11 ≠ 15

The ordered pair do not satisfy the second equation.

Hence,

(2,7) is not a solution to the given system of equations.

8 0
3 years ago
3(x^2+4x)+4(y^2-2y)=32
nekit [7.7K]

Answer:

3x^2 + 12x + 4y^2 - 8y = 32

Step-by-step explanation:

3(x^2+4x)+4(y^2-2y)=32

At first we have to break the parenthesis to get the variables in normal position. To break those, we have to multiply each with the help of algebraic expression:

or, (3*x^2) + (3 × 4x) + (4 × y^2) - (4 × 2y) = 32

or, 3x^2 + 12x + 4y^2 - 8y = 32

Since the equation does not have anything to add or deduct, therefore, it is the answer.

5 0
3 years ago
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