The length of section 1 is 0.75 m and the length of section 2 is 15/100 m. The total length of the section is equal to the sum of section 1 and section 2. So, we will add them as follows :

$l=0.75\ m+\dfrac{15}{100}\ m\\\\\because \dfrac{15}{100}=0.15\\\\l=0.75\ m +0.15\ m\\\\l=0.9\ m$

So, the length of the section is 0.9 m or 9/10 m

8 0

3 years ago

Which one is bigger 13yards or 282 inches

olganol [36]

Answer:

13yards

Step-by-step explanation:

4 0

3 years ago

Semicircles

Studentka2010 [4]

Answer:

The area of the shaded portion of the figure is $9.1\ cm^2$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shaded area is equal to the area of the square less the area not shaded.

There are 4 "not shaded" regions.

step 1

Find the area of square ABCD

The area of square is equal to

$A=b^2$

where

b is the length side of the square

we have

$b=4\ cm$

substitute

$A=4^2=16\ cm^2$

step 2

We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):

The area of circle is equal to

$A=\pi r^{2}$

The diameter of the circle is equal to the length side of the square

$r=\frac{b}{2}=\frac{4}{2}=2\ cm$ ---> radius is half the diameter

substitute

$A=\pi (2)^{2}$

$A=4\pi\ cm^2$

Therefore, the area of 2 "not-shaded" regions is:

$A=(16-4\pi) \ cm^2$

and the area of 4 "not-shaded" regions is:

$A=2(16-4\pi)=(32-8\pi)\ cm^2$

step 3

Find the area of the shaded region

Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:

$A=16-(32-8\pi)=(8\pi-16)\ cm^2$

---> exact value

assume

$\pi =3.14$

substitute

$A=(8(3.14)-16)=9.1\ cm^2$

8 0

3 years ago

PLEASE ANSWER IF YOU CAN!!

Andrew [12]

Answer:

the surface area of the decoration is 31.5

Step-by-step explanation:

3 0

3 years ago

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