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3 years ago

If you're good at trig please help meeeee

Mathematics

1 answer:

tino4ka555 [31]3 years ago

4 0

Answer:

x ≈ 77°, y = 103°

Step-by-step explanation:

Using the Sine rule in Δ BCD

$\frac{2.9}{sin45}$ = $\frac{4}{sinx}$ ( cross- multiply )

2.9sinx° = 4sin45° ( divide both sides by 2.9 )

sinx° = $\frac{4sin45}{2.9}$ , thus

x = $sin^{-1}$ ( $\frac{4sin45}{2.9}$ ) ≈ 77° ( to the nearest degree )

Since AC and DC are congruent then Δ ACD is isosceles.

Thus the base angles are congruent, that is

∠ ADC = ∠ CAD = y°

x and y are adjacent angles and supplementary, thus

x + y = 180, that is

77 + y = 180 ( subtract 77 from both sides )

y = 103°

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Answer:

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Step-by-step explanation:

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3 years ago

Help me asap! I will give you marks

Law Incorporation [45]

Recall the binomial theorem.

$(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k$

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$\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}$

Observe that

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$k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2$

When we multiply these by $8-9x$ ,

• $8$ and $\frac73 x^2$ combine to make $\frac{56}3 x^2$

• $-9x$ and $\frac73 x$ combine to make $-\frac{63}3 x^2 = -21x^2$

and the sum of these terms is

$\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}$

2. The binomial expansion is

$\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k$

We get the $a^6b^2$ term when $k=2$ :

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1 year ago

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Answer:

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3 years ago

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3 years ago

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4 years ago