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SIZIF [17.4K]
3 years ago
12

PLEASE HELP ME IF YOU CAN! please tell me how you got the answer thank you!

Mathematics
1 answer:
Law Incorporation [45]3 years ago
8 0

Answer:

D) 35.6

Step-by-step explanation:

Use pythagorean theorem

22^2 + 28^2 = 1268

Take square root of 1268, which equals to 35.60898763.

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And the difference between the range and the mean (15. 13. 22, 18, 13. 12. 18, 16, 14, 18, 14)​
Sladkaya [172]

Answer:

range °° heights - lowest = 22-12 = 10

mean °° average number = sum of all numbers÷ number of digits = 173÷ 11 =15.727

5 0
3 years ago
What is the elapsed time between 3:40 AM and 2 PM?
UNO [17]
<span>10 hrs 20 mins just count and when you get to 12, go back to 1 but make sure you change it to either PM or AM</span><span />
5 0
3 years ago
Please help. I don't understand​
Andreas93 [3]

Answer:

Length of third side is: \mathbf{8m^3-4m^2+3m}

Step-by-step explanation:

Perimeter of triangle = 18m^3+2m^2-m

Length of side 1= 5m^3+3m^2-2m

Length of side 2= 5m^3+3m^2-2m

We need to find length of third side.

The formula used is: Perimeter \:of\:triangle=Sum\:of\:all\:sides

Putting values and finding length of third side.

Perimeter \:of\:triangle=Sum\:of\:all\:sides\\18m^3+2m^2-m=5m^3+3m^2-2m+5m^3+3m^2-2m+Length\:of\:3rd\:side\\18m^3+2m^2-m=5m^3+5m^3+3m^2+3m^2-2m-2m+Length\:of\:3rd\:side\\18m^3+2m^2-m=10m^3+6m^2-4m+Length\:of\:3rd\:side\\Length\:of\:3rd\:side=18m^3+2m^2-m-(10m^3+6m^2-4m)\\Length\:of\:3rd\:side=18m^3+2m^2-m-10m^3-6m^2+4m\\Length\:of\:3rd\:side=18m^3-10m^3+2m^2-6m^2-m+4m\\Length\:of\:3rd\:side=8m^3-4m^2+3m

So, Length of third side is: \mathbf{8m^3-4m^2+3m}

5 0
3 years ago
Will give Brainliest !! ANSWER 13,14 and 19!
pav-90 [236]

Answer:

13 1 line

14 2/3 1/2

19 top 123 bottom 4

Step-by-step explanation:

6 0
3 years ago
Refer to the following distribution:Cost of Textbooks Frequency $25 up to $35 2 S35 up to $45 5$45 up to $55 7$55 up to $65 20 S
soldi70 [24.7K]

Answer:

Relative\ Frequency = 0.04

Step-by-step explanation:

Given

Cost of Textbooks ---- Frequency

$25 up to $35  -----      2

$35 up to $45 -------     5

$45 up to $55  -------    7

$55 up to $65   ------    20

$65 up to $75   ----   -- 16

Required

Determine the relative class frequency for the $25 up to $35 class

First, we need to get the total frequency

Total = 2 + 5 + 7 + 20 + 16

Total = 50

Next, is to write out the frequency of $25 up to $35 class

Frequency = 2

Divide this frequency by the total frequency; This gives the relative frequency

Relative\ Frequency = \frac{Frequency}{Total}

Relative\ Frequency = \frac{2}{50}

Relative\ Frequency = 0.04

Hence;

Option D answers the question

4 0
3 years ago
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