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3 years ago

PLZ HELP MEEEEE!!!! ILL GIVE YOU BRAINLY!!

Mathematics

1 answer:

valkas [14]3 years ago

8 0

Answer:

Step-by-step explanation: -13, 9

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What is the complete factorization of 3x2 + 22x − 16?

EleoNora [17]

Answer:

controller

Step-by-step explanation:

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3 years ago

I really don’t get this how do I do this:(?

Crazy boy [7]

Answer:

You are drawing a right triangle. So draw the two lines off of the right angle. Then write 5 along one line. That line is now BC, so you can start naming points and putting in lengths. Then, draw the hypotenuse (AB) going from the end of the line you were writing next to, to the other line. Make sure it is at least twice as long, because it is 13 long. Then, to find the length of the last line, square 13, and subtract 25 from it. Take that number and find it's square root. You should get 12, which is your answer.

Step-by-step explanation:

4 0

3 years ago

Okay Ju|ian Foley simplifies this polynomial and then write it in standard form if Ju|ian wrote it the last term

Fudgin [204]

Answer:

the second choice

Step-by-step explanation:

8 0

3 years ago

I need clean and clear answers please!<br><br> Thank you

lina2011 [118]

Okay so we get: subtract m + 8 from 5m + 11

5m + 11 = 16 + m or 16m

16m - 8 +m or 8m = 8m or 8 + m

5 0

3 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

3 0

3 years ago