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Lapatulllka [165]
4 years ago
8

Which statement is true about the product square root of 2(5 + square root of 8)?

Mathematics
2 answers:
Serggg [28]4 years ago
8 0

For this case we have the following product:

\sqrt{2}(5+\sqrt{8})

Applying the distributive property we have:

5\sqrt{2}+\sqrt{2}\sqrt{8}

Then, rewriting the expression we have:

2\sqrt{2}\sqrt{2}+5\sqrt{2}

4+5\sqrt{2}

We note that the answer is a irrational number, because the square root of two is not an exact number.

Answer:

4+5\sqrt{2}

It is irrational and equal to 4 + 5square root of 2.

Yuki888 [10]4 years ago
3 0
We are given with two factors: square root of 2 and 5 + square root of 8. We use a scientific calculator that displays irrational answers. The product of the two factors is 4 + 5 square root of 2. The answer is irrational since the square root sign in the answer is present.
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3 years ago
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The sum of the first 5 terms of an AP is 30 and the sum of the four term from T6 to T9 (inclusive) is 69. Find the AP​
Ainat [17]

Answer: The AP = 1, ⁷/₂, 6, ¹⁷/₂, 11 ..............

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From the first statement,

S₅ = ⁵/₂(2a + ( n - 1 )d }    = 30

       5(2a  + 4d )d           = 60

       10a    + 20d             = 60

reduce to lowest term to easy calculation by dividing through by 10

                      a + 2d       = 6 -----------------------------------1

second statement

sum of the next 4 terms inclusive

T₉  = ⁹/₂(2a + 8d )   = 69

        9(2a  + 8d )    = 30 + 69

            18a + 72d   = 99 x 2

            18a + 72d   = 198

divide through by 18 to reduce to lowest time

                a  + 4d    = 11 ------------------------------------------2

Now solve the two equation simultaneously to find a and d

                 a + 2d = 6

                 a + 4d = 11

                     -2d  = -5

                          d = ⁵/₂.

Now substitute  for d to get a

               a  + 2(⁵/₂) = 6

                a + 5       = 6

                           a   = 6 - 5

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Therefore the AP = 1 , ⁷/₂ , 6 , ¹⁷/₂ , 11 , ..............

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