Answer:
decrease of 38% (to nearest percent)
Step-by-step explanation:
Percent change = [ (difference between final and initial value) ÷ initial value] x 100
⇒ percent change = [(2100 - 1300) ÷ 2100] × 100 = 38% (to nearest percent)
Answer:
Step-by-step explanation:
Answer:
y=-2x+2
slope-intercept form --> y=mx+b
m= slope. the slope in the graph is down 2 over 1, -2/1 which is the same as -2.
b = <u>y-intercept</u><u>. </u><u> </u><u>the </u><u>y-intercept</u><u> </u><u>is </u><u>2</u><u>.</u>
Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15
a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005
b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
