Answer:
Step-by-step explanation:
The type I error occurs when the researchers rejects the null hypothesis when it is actually true.
The type II error occurs when the researchers fails to reject the null hypothesis when it is not true.
Null hypothesis: The proportion of people who write with their left hand is equal to 0.23: p =0.23
Type I error would be: Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually different from 0.29
Since 0.29 is assumed to be the alternative claim.
Type II error would be: Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29
Still with the assumption that 0.29 is the alternative claim.
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8:32 simplyfies to 1:4 .....there is your answer 1:4
Answer:
Step-by-step explanation:
To solve this, we would follow these simple steps. We have
unvrs :
The arithmetic mean, x-bar for the yellow paper group (Y) = 20.6
The arithmetic mean, x-bar for the green paper group (G) = 21.75
Recall that, H0: µY = µG
And from the data we have, we can see that
H0: µY< µG
We proceed to say that the
T-Test-statistic = -0.404
Also, the p-value: 0.349
From our calculations, we can see that the p-value > 0.05, and as such, we conclude that we will not reject H0. This is because there is not enough evidence to show that test that is printed on the yellow paper decreases anxiety at a 0.05 significance level.
B 216 because if you multiply pi with the answer you get 678.58
