Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
Answer:
(A) 0.006593 or 0.6593%
(B) 0.01538 or 1.538%
Step-by-step explanation:
The total number of possibilities to pick 3 parts out of 15 possible parts is given by the following combination:

(A) There are only three possibilities for which the inspector finds exactly one nonconforming part (NCC, CNC, CCN). Therefore, the probability is:

(B) There are three possibilities for which the inspector finds exactly one nonconforming part, three possibilities for two nonconforming parts (NNC, CNN, NCN), and one possibility for all nonconforming parts (NNN). The probability that the inspector finds at least one nonconforming part is:

Answer:
the answer is 14,880 and its bigger :D 14880>12400
Step-by-step explanation:
Answer:
Step-by-step explanation:
The determinant of a matrix is a special number that can be calculated from a square matrix.
...
To work out the determinant of a 3×3 matrix:
Multiply a by the determinant of the 2×2 matrix that is not in a's row or column.
Likewise for b, and for c.
Sum them up, but remember the minus in front of the b.
Assuming width=diameter
diameter/2=radius
area=hpir^2
w=d=2
d/2=2/2=1=r
h=6
area=6pi1^2
area=6pi1
area=6pi
aprox pi=3.141592
area=18.85 cm³