Answer:The diagram shows a square ABCD.
D
N
bu
A
M
I
Mis the midpoint of AB.
Nis the midpoint of AD.
The area of the shaded triangle AMN is 18 cm
Work out the area of triangle MCN.
5b is the area of MCN
Step-by-step explanation:
The question in Englih is
<span>From a cardboard sheet 35 cm long and 20 cm wide, Masha cut out four squares of 1 dm2 each. Find the area of the cardboard residue. Answer the question in dm2
</span>
Step 1
<span>convert cm to dm
</span>we know that
1 cm is---------------> 0.10 dm
then
35 cm--------------> 3.5 dm
20 cm--------------> 2 dm
Step 2
find the area of the cardboard
Area=3.5*2=7 dm²
Step 3
find the area of the cardboard residue
Area=7-4*1=3 dm²
the answer is 3 dm²
<span>the answer in Russian
</span>
Шаг 1
преобразовать cm в дм
мы знаем это
1 cm ---------------> 0.10 дм
тогда
35 cm--------------> 3.5 дм
20 cm--------------> 2 дм
Шаг 2
найти область картона
Площадь=3.5*2=7 дм²
Шаг 3
<span>найти область остатка картона
</span>Площадь=7-4*1=3 дм²
ответ 3 дм²
ответ 3 дм²
Answer:
174.6 ft
Step-by-step explanation:
It can be helpful to draw a diagram of the triangle we're concerned with. (See attached.)
We know the angle at the end of the shadow inside the triangle is 52°-22° = 30°. We assume the tree is growing straight up out of the hillside, so its angle with the hill inside the triangle is 90°+22° = 112°. Then the remaining angle between the shadow and the tree at the top of the tree is ...
180° -30° -112° = 38°
Now, we have the angle opposite the tree, and the angle opposite the known side length of the triangle (215 feet along the hill, AC in the diagram). This is enough information to usefully use the Law of Sines.
c/sin(C) = a/sin(A)
c = a(sin(C)/sin(A)) = (215 ft)(sin(30°)/sin(38°)) ≈ 174.6 ft
The height of the tree is about 174.6 feet.
Can u send me a picture of the question instead please because i dont understand what ur trying to ask..