(c+8)(c-8)
3(2y+5)(2y-5)
There are no like terms so it's still ab^2-b
Answer: All but one was right
1. 0 (correct)
2. 34 (correct)
3. 398 (correct)
4. -350 (correct)
5. 20 (correct)
6. 200 (wrong)
7. 48 (correct)
8. -1000(correct)
9. 150 (correct)
10. -55 (correct)
Step-by-step explanation:
(2x5)x(9÷3)+4=10x3+4=30+4=34
4(25x8÷2)+3-5=4(200÷2)+3-5=4x100+3-5=400+3-5=403-5=398
-10x20-30(5)=-200-150=-350
5x10-30=50-30=20
4(50-20÷4)+20=4(50-5)+20=4x45+20=180+20=200
3x4(20÷5)=12x4=48
-20(50x2)+5(200)=-20x100+5x200= -2000+1000=-1000
20x5+70-20=100+70-20=170-20=150
-5+10x(-5)==5+-50=-55
Answer:
$20
Step-by-step explanation:
50% of Fundraising goal= 0.5 x $40
= $20
The customer gives you:
-- a ticket worth . . . . . . 5
-- a ticket worth. . . . . . . 2
-- a bill. . . . . . . . . . . . 100
------------------------
-- Total. . . . . . . . . . . . 107
You give the customer:
-- gas worth . . . . . . . . 17.01
-- a ticket worth . . . . . . 5
-- two $1 tickets worth . 2
-- a ticket worth . . . . . . 3
------------------------------
-- Total . . . . . . . . . . . . 27.01
In order to make the trade even, you owe the customer
(107.00 - 27.01) = <em>$79.99 more
</em><em>
</em>You could give it to him in the form of some combination of magazines,
soda, cigarettes, gum, newspapers, motor oil, car deodorizers, candy
bars, washer fluid, anti-freeze, etc. But he'd be there all day trying to
decide what he wants and making it all add up to exactly $79.99, and
there's a long line of other customers waiting behind him.
That's the beauty of cash money. You can count out exactly the proper
amount, it only takes a few seconds and bada-bing, he's out of there and
back on the road.
Answer:
a) dx/dt = kx*(M - h/k - x)
Step-by-step explanation:
Given:
- The harvest differential Equation is:
dx/dt = kx*(M-x)
Suppose that we modify our harvesting. That is we will only harvest an amount proportional to current population.In other words we harvest hx per unit of time for some h > 0
Find:
a) Construct the differential equation.
b) Show that if kM > h, then the equation is still logistic.
c) What happens when kM < h?
Solution:
- The logistic equation with harvesting that is proportional to population is:
dx/dt = kx*(M-x) hx
It can be simplified to:
dx/dt = kx*(M - h/k - x)
- If kM > h, then we can introduce M_n=M -h/k >0, so that:
dx/dt = kx*(M_n - x)
Hence, This equation is logistic because M_n >0
- If kM < h, then M_n <0. There are two critical points x= 0 and x = M_n < 0. Since, kx*(M_n - x) < 0 for all x<0 then the population will tend to zero for all initial conditions