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andriy [413]
1 year ago
13

Zen design a character for a video game he just three sizes of the character on grid paper then uses the expression 6+ X to the

power of two to find the number of grid squares in a character of any size S find the number of grade squares in a character of size 7 show your work
Mathematics
1 answer:
RoseWind [281]1 year ago
4 0

If Zen design a character for a video game he just three sizes of the character on grid paper then uses the expression 6+ X to the power of two.  the number of grid squares in a character of size 7 is 55.

<h3>Number of grid square</h3>

Given:

Expression=6+x²

Now using the expression to determine the number of grid square in a character of size 7.

Expression=6+x²

Where:

x=7

Hence,

6+7²

=6+49

x=55

Therefore If Zen design a character for a video game he just three sizes of the character on grid paper then uses the expression 6+ X to the power of two.  the number of grid squares in a character of size 7 is 55.

Learn more about grid square here:brainly.com/question/1123971

#SPJ1

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Factor these expressions into an equivalent form.
Marrrta [24]
(c+8)(c-8)

3(2y+5)(2y-5)

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7 0
3 years ago
Read 2 more answers
Check please :D <br> 12345678901234567890
bagirrra123 [75]

Answer: All but one was right

1. 0 (correct)

2. 34 (correct)

3. 398 (correct)

4. -350 (correct)

5. 20 (correct)

6. 200 (wrong)

7. 48 (correct)

8. -1000(correct)

9. 150 (correct)

10. -55 (correct)

Step-by-step explanation:

(2x5)x(9÷3)+4=10x3+4=30+4=34

4(25x8÷2)+3-5=4(200÷2)+3-5=4x100+3-5=400+3-5=403-5=398

-10x20-30(5)=-200-150=-350

5x10-30=50-30=20

4(50-20÷4)+20=4(50-5)+20=4x45+20=180+20=200

3x4(20÷5)=12x4=48

-20(50x2)+5(200)=-20x100+5x200= -2000+1000=-1000

20x5+70-20=100+70-20=170-20=150

-5+10x(-5)==5+-50=-55

6 0
2 years ago
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Sarah was raising money for a fundraiser. Her fundraising goal was $40. What would 50% of her fundraising goal be??
Delvig [45]

Answer:

$20

Step-by-step explanation:

50% of Fundraising goal= 0.5 x $40

                                        = $20

4 0
3 years ago
a costumer buys 17.01 in gas and requests one five dollar ticket, two one dollar tickets, and one three dollar ticket. he gives
marin [14]

The customer gives you:
-- a  ticket worth . . . . . . 5
-- a ticket worth. . . . . . . 2
-- a bill. . . . . . . . . . . . 100
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-- Total. . . . . . . . . . . . 107

You give the customer:
-- gas worth . . . . . . . . 17.01               
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-- two $1 tickets worth . 2
-- a ticket worth . . . . . . 3
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-- Total . . . . . . . . . . . . 27.01

In order to make the trade even, you owe the customer

                               (107.00  -  27.01)  =  <em>$79.99 more
</em>
<em>
</em>You could give it to him in the form of some combination of magazines,
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8 0
3 years ago
Start with the logistic equation dx dt kx(M−x). Suppose we modify our harvesting. That is we will only harvest an amount proport
Marina CMI [18]

Answer:

a) dx/dt = kx*(M - h/k - x)

Step-by-step explanation:

Given:

- The harvest differential Equation is:

                            dx/dt = kx*(M-x)

Suppose that we modify our harvesting. That is we will only harvest an amount proportional to current population.In  other  words  we  harvest hx per  unit  of  time  for  some h > 0

Find:

a) Construct the differential equation.  

b) Show that if kM > h, then the equation is still logistic.

c) What happens when kM < h?

Solution:

- The logistic equation with harvesting that is proportional to population is:

                               dx/dt = kx*(M-x) hx

It can be simplified to:

                              dx/dt = kx*(M - h/k - x)

- If kM > h, then we can introduce M_n=M -h/k >0, so that:

                              dx/dt = kx*(M_n  - x)  

Hence, This equation is logistic because M_n >0

- If kM < h,  then M_n <0. There are two critical points x= 0 and x = M_n < 0. Since, kx*(M_n  - x)  < 0 for all x<0 then the population will tend to zero for all initial conditions

6 0
3 years ago
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