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Natalka [10]
3 years ago
7

Name all 6 trigonometric ratios

Mathematics
1 answer:
netineya [11]3 years ago
3 0

Answer:

\displaystyle \frac{OPPOSITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOSITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOSITE} = csc\:θ \\ \frac{ADJACENT}{OPPOSITE} = cot\:θ

I am joyous to assist you anytime.

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Musya8 [376]
Yes the quotient of 9 is rational
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3 years ago
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To solve problems about spans of time that include B.C. and A.D. dates, you would need to use which numbers?
Studentka2010 [4]

The correct numbers to use in solving problems about spans of time like B.C. and A.D. should be “integers”.

Integers are whole numbers (not a fractional number or not a decimal number) which can take a value of negative, zero, or positive number. Example of integers would be -1, 0 and 1.

<span>In calculations, the time period would be on the x-axis. Since B.C. and A.D. are two different spans of time, therefore in the calculations, the date of BC should be negative (negative x-axis) while the date of AD should be positive (positive x-axis). This would place the origin as the common reference.</span>

3 0
3 years ago
Jane, Jasmine, and Jocelyn have record collections. Jane has 3 times as many records as Jocelyn has. Jasmine has 2 more than twi
dangina [55]
X = jane, y = jasmine, z = jocelyn

x + y + z = 56
x = 3z
y = 2z + 2

3z + 2z + 2 + z = 56
6z + 2 = 56
6z = 56 - 2
6z = 54
z = 54/6
z = 9 <==== jocelyn

x = 3z
x = 3(9)
x = 27 <=== jane

y = 2z + 2
y = 2(9) + 2
y = 18 + 2
y = 20 <=== jasmine
7 0
3 years ago
A floor of a room is in the shape of square. It is to be covered with rectangular tiles that each have an area of 192 square inc
Grace [21]
Find area of room
aera=legnth wtimes width
in a square, legnth=width
aera=legnth^2
legnth=14 feet
convert o inches
14*12=168 inches
area=168^2=28224 square inches

how many tiles will cover all of floor?
aka
how many 192 in^2 is at least 28224 (at least, because we need to cover the whole floor without gaps)
192x<u>></u>28224
divide both sides by 192
x<u>></u>147

147 is the number of tiles we need

8 0
3 years ago
Read 2 more answers
The weight of an organ in adult males has a bell-shaped distribution with a mean of 310 grams and a standard deviation of 25 gra
Shkiper50 [21]

Answer:

About 68% of organs will be between 300 grams and 320 grams, about 95% of organs will be About 68% of organs will be between 300 grams and 320 grams, About 68% of organs will be between 300 grams and 320 grams, about 95% of organs will be between 280 grams and 360 grams, the percentage of organs weighs less than 280 grams or more than 360 grams is 5%, and the percentage of organs weighs between 300 grams and 360 grams is 81.5%.

Given :

The weight of an organ in adult males has a bell-shaped distribution with a mean of 320 grams and a standard deviation of 20 grams.

A) According to the empirical rule, using the values of mean and standard deviation:

\rm \mu-\sigma = 320-20=300 \; gramsμ+σ=320+20=320grams

Therefore, about 68% of organs will be between 300 grams and 320 grams.

B) Again according to the empirical rule, using the values of mean and standard deviation:

\rm \mu-2\times \sigma = 320-40=280 \; gramsμ−2×σ=320−40=280grams

\rm \mu+2\times \sigma = 320+40=360 \; gramsμ+2×σ=320+40=360grams

Therefore, according to the empirical rule, about 95% of organs will be between 280 grams and 360 grams.

C)

The percentage of organs weighs less than 280 grams or more than 360 grams = 100 - (The percentage of organs weighs between 280 grams and 360 grams)

The percentage of organs weighs less than 280 grams or more than 360 grams = 100 - 95 = 5%

D)

The percentage of organs weighs between 300 grams and 360 grams = 0.5 \times× ( percentage of organs weighs between 280 grams and 360 grams + percentage of organs weighs between 300 grams and 320 grams)

The percentage of organs weighs between 300 grams and 360 grams = 0.5 \times× (95 + 68)

So, the percentage of organs weighing between 300 grams and 360 grams is 81.5%.

For more information, refer to the link given below:

brainly.com/question/23017717 95% of organs will be between 280 grams and 360 grams, the percentage of organs weighs less than 280 grams or more than 360 grams is 5%, and the percentage of organs weighs between 300 grams and 360 grams is 81.5%.

Given :

The weight of an organ in adult males has a bell-shaped distribution with a mean of 320 grams and a standard deviation of 20 grams.

A) According to the empirical rule, using the values of mean and standard deviation:

\rm \mu-\sigma = 320-20=300 \; gramsμ−σ=320−20=300grams

\rm \mu+\sigma = 320+20=320 \; gramsμ+σ=320+20=320grams

Therefore, about 68% of organs will be between 300 grams and 320 grams.

B) Again according to the empirical rule, using the values of mean and standard deviation:

\rm \mu-2\times \sigma = 320-40=280 \; gramsμ−2×σ=320−40=280grams

\rm \mu+2\times \sigma = 320+40=360 \; gramsμ+2×σ=320+40=360grams

Therefore, according to the empirical rule, about 95% of organs will be between 280 grams and 360 grams.

C)

The percentage of organs weighs less than 280 grams or more than 360 grams = 100 - (The percentage of organs weighs between 280 grams and 360 grams)

The percentage of organs weighs less than 280 grams or more than 360 grams = 100 - 95 = 5%

D)

The percentage of organs weighs between 300 grams and 360 grams = 0.5 \times× ( percentage of organs weighs between 280 grams and 360 grams + percentage of organs weighs between 300 grams and 320 grams)

The percentage of organs weighs between 300 grams and 360 grams = 0.5 \times× (95 + 68)

So, the percentage of organs weighing between 300 grams and 360 grams is 81.5%.

For more information, refer to the link given below:

brainly.com/question/23017717

5 0
3 years ago
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