All categories

3 years ago

Can someone please give me the (Answers) to this? ... please ... I need help….

Mathematics

1 answer:

Nana76 [90]3 years ago

3 0

The geometric mean is defined as the nth root of the product of n numbers

1. 4 and 9

Geometric mean = $\sqrt{4*9} = \sqrt{36} =6$

2. 5 and 8

Geometric mean = $\sqrt{5*8} =\sqrt{40} = 2\sqrt{10}$

3. 8 and 32

Geometric mean = $\sqrt{8*32} =\sqrt{256} =16$

4. 64 and 36

Geometric mean = $\sqrt{64*36} =\sqrt{2304}=48$

Hope that helped!

You might be interested in

22.5% written as a fraction in simplest form

nata0808 [166]

22.5% written as a fraction in simplest form is 9/40 . Hope i helped.

3 0

3 years ago

A ball was drawn from a bag containing 10 red, 30 white, 20 blue, and 15 yellow balls. what is the probability that it is neithe

Wittaler [7]

There are a total of 75 balls in the bag.

45 of these balls are neither red nor blue.

45/75 = .60

There is a 60% chance that a ball that in not red or blue will be chosen.

Hope this helps!

7 0

4 years ago

The circle below is centered at the origin and has a radius of 10. What is its<br> equation?

xz_007 [3.2K]

Answer:

x^2 + y^2 = 100

Step-by-step explanation:

The general form of the equation of a circle is

(x-h)^2+(y-k)^2 = r^2

where (h,k) is the center and r is the radius

(x-0)^2+ (y-0)^2 = 10^2

x^2 + y^2 = 100

3 0

3 years ago

F = 1.8 C + 32<br> (a) Work out the value of F when C = -8

dybincka [34]

Answer:

17.6°

Step-by-step explanation:

1.8x-8=-14.4

-14.4 + 32= 17.6°C

5 0

3 years ago

A Mexican restaurant sells quesadillas in two sizes: a "large" 10 inch-round quesadilla and a "small" 5 inch-

elena-14-01-66 [18.8K]

Answer:

Half of the 10-inch quesadilla is greater than the entire 5-inch quesadilla

Step-by-step explanation:

we know that

The area of a circle is equal to

$A=\pi r^2$

where

r is the radius

step 1

Find the area of the 10 inch-round quesadilla

we have

$D=10\ in$

$r=10/2=5\ in$

substitute

$A=\pi (5)^2$

$A=25\pi\ in^2$

step 2

Find the area of the 5 inch-round quesadilla

we have

$D=5\ in$

$r=5/2=2.5\ in$

substitute

$A=\pi (2.5)^2$

$A=6.25\pi\ in^2$

step 3

Which is larger, half of the 10-inch quesadilla or the entire 5-inch quesadilla?

Compare

half of the 10-inch quesadilla is equal to ----> $\frac{1}{2}(25\pi)=12.5\pi\ in^2$

the entire 5-inch quesadilla ----> $6.25\pi\ in^2$

therefore

Half of the 10-inch quesadilla is greater than the entire 5-inch quesadilla

3 0

3 years ago

￼Can someone please give me the (Answers) to this? ... please ... I need help….

Can someone please give me the (Answers) to this? ... please ... I need help….