Answer:
3x
Step-by-step explanation:
Answer:
C. Kalena made a mistake in Step 3. The justification should state: -x²
+ x²
Step-by-step explanation:
Given the function x(x - 1)(x + 1) = x3 - X
To justify kelena proof
We will need to show if the two equations are equal.
Starting from the RHS with function x³-x
First we will factor out the common factor which is 'x' to have;
x(x²-1)
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Note that for two real number a and b, the expansion of a²-b² using difference vof two square will give;
a²-b² = (a+b)(a-b) hence;
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Factorising x(x+1) gives x²+x, therefore
x(x+1)(x-1) = (x²+x)(x-1)
(x²+x)(x-1) = x³-x²+x²-x
The function x³-x²+x²-x gotten shows that kelena made a mistake in step 3, the justification should be -x²+x² not -x-x²
Answer:
Shorter piece= 4 ft, longer piece= 13 ft
Step-by-step explanation:
If shorter piece is x
Longer pc is 2x + 5
Together they make 17 feet
So x + 2x + 5 = 17
3 x + 5 = 17
3x = 17 - 5 = 12
3x = 12
X = 12/ 3 = 4
So shorter pc is 4 feet
Longer pc is 2 x + 5
= (2 x 4) + 5
= 8 + 5 = 13
<h2>10/5=2 test per week</h2><h2>7x2=14</h2><h2>Josh took 14 test in 7 weeks</h2>
<h3>
Answer: 16</h3>
=============================================================
Explanation:
Equate s(t(x)) and s(1) to find that t(x) = 1 must be the case.
Let's find what x must be.
t(x) = 3x-8
1 = 3x-8
1+8 = 3x
9 = 3x
3x = 9
x = 9/3
x = 3
So plugging x = 3 into t(x) gets us t(x) = 1
In other words, t(3) = 1
So that tells us s(t(3)) = s(1)
-------------
Let's plug x = 3 into the s(t(x)) equation
s(t(x)) = x^2 + 3x - 2
s(t(3)) = (3)^2 + 3(3) - 2
s(1) = 9 + 3(3) - 2
s(1) = 9 + 9 - 2
s(1) = 18 - 2
s(1) = 16
