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3 years ago

Xiang is a teacher who bought a $2350 laptop for school use. The laptop is an allowable

Mathematics

1 answer:

Nata [24]3 years ago

3 0

Answer:

Step-by-step explanation:

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You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta

vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

$m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$m = -\frac{\cos 2\theta}{\sin \theta}$

The tangent line is horizontal when $m = 0$ . Then:

$\cos 2\theta = 0$

$2\theta = \cos^{-1}0$

$\theta = \frac{1}{2}\cdot \cos^{-1} 0$

$\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right)$ , for all $i \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}$ , for all $i \in \mathbb{N}_{O}$

The first four solutions are:

x: $\sqrt{2}$ $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$

y: 1 -1 1 -1

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

6 0

2 years ago

s quadrilateral JKLM the result of a dilation of quadrilateral ABCD by a scale factor of 2? Why or why not?

Likurg_2 [28]

If quadrilateral JKLM has given values, as well as quadrilateral ABCD, it can be concluded from the given values if JKLM is a result of a dilation of ABCD by a scale factor of 2. Dilation factor is used to scale up a given figure. If ABCD has measurements of 1, 2, 3, and 4. Then the measurements of JKLM should be 4, 8, 12, and 16.

4 0

3 years ago

Jack bought 4 dozen eggs at $10 per dozen. 6 were broken. what percent of his money goes to waste

erik [133]

he paid = 4*10 = $40

48 eggs = $40

so, waste money would be 6/48 * 100 = 12.5%

5 0

3 years ago

Write in standard notation. 6.12 X 10^3

charle [14.2K]

6120 is your answer. scientific/standard notation is very easy. if you need help understanding, pm me :)